Need some hints for a Coulomb's Law question

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    Coulomb's law Law
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Homework Help Overview

The problem involves a piece of paper with a known charge and mass, which is influenced by an unknown charge from a comb. The context is based on Coulomb's Law and the forces acting on the paper due to electrostatic attraction.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the force required to lift the paper and whether this force can be equated to the electrostatic force between the paper and the comb. There are questions about the calculation of the charge on the comb and the number of excess electrons.

Discussion Status

Participants are actively engaging with the problem, confirming that the approach of using weight to find the required force is valid. Some have provided hints and checks on calculations, while others have expressed gratitude for the guidance received.

Contextual Notes

There are indications of potential confusion regarding the magnitude of the calculated charge and the number of electrons, suggesting that participants are still clarifying their understanding of the problem's parameters.

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Homework Statement


Suppose that resting on your non-conducting desktop is a tiny piece of paper(m=0.08g) that carries a charge of +4 x 10-10C. You comb your hair and then slowly lower your comb until when it is 3 cm away from the paper, the paper jumps up to the comb.
a) Give an approximate value for the charge on the comb.
b) Does the comb carry an excess of electrons or protons? How many?

Homework Equations


Coulomb's Law:
F=(1/4*pi*E0)*(|Q1Q2|/r2)
Magnitude of charge of electron and proton: e=1.60217 x 10-19
Q=ne

The Attempt at a Solution


I know that we have to consider w=mg since there is mass involved for the paper. I tried to use Coulomb's Law to find the charge, but I don't know what the Force is between the two, so how can I find charge for the comb? I've converted the given numbers to the right units which are 0.08g = 0.8 x 10-4 and 3cm = 0.03m.
Now, my question is, can anyone give me a hint on how to start this question?
 
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What force is required to lift a piece of paper that has mass 0.08 grams?
 
gneill said:
What force is required to lift a piece of paper that has mass 0.08 grams?

That would be w=mg! But can I use this force as the force between the two objects? If so, I will then be able to solve for the unknown charge.

Am I on the right track?
 
whatisphysics said:
That would be w=mg! But can I use this force as the force between the two objects? If so, I will then be able to solve for the unknown charge.

Am I on the right track?

Yes, yes you are!
 
gneill said:
Yes, yes you are!

Thanks so much for the hint! Just one small question, for calculating the number of electrons(excess electrons of comb);I do Q=ne which is:

1.96x10-7C = n*1.60x10-19C
and I will get e = 1.23x1012. [tex]\leftarrow[/tex]This is the number of electrons right?

Thanks again!
 
Your unknown charge looks to be a bit large (by several orders of magnitude). Maybe you can check or show your calculation.

Your method for finding the number of electrons transferred looks fine.
 
Hey, just had to come back here to say thanks again. I asked my teacher the same question, and it turned out right!

Thanks a bunch.
 

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