Need to find the equivalence point volume from the first derivative graph?

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SUMMARY

The discussion centers on determining the equivalence point volume during a titration of 0.2M NaOH with acetic acid, utilizing the first derivative graph of pH versus volume. The participants confirm that the equivalence point is identified by the intersection of two trend lines drawn from the left and right of the graph, rather than forcing the lines through the highest slope point. The consensus suggests that the equivalence point volume is approximately 19.97 mL, acknowledging the potential inaccuracies in slope measurements.

PREREQUISITES
  • Understanding of titration principles and equivalence points
  • Proficiency in using Excel for graphing and data analysis
  • Knowledge of first derivative calculations in chemistry
  • Familiarity with slope interpretation in graphical data
NEXT STEPS
  • Learn advanced Excel techniques for trend line analysis
  • Study the concept of derivatives in the context of chemical titrations
  • Explore methods for minimizing measurement inaccuracies in titration experiments
  • Investigate the impact of different concentrations on equivalence point determination
USEFUL FOR

Chemistry students, laboratory technicians, educators in analytical chemistry, and anyone involved in titration experiments seeking to enhance their understanding of equivalence point determination.

crimsonn
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Homework Statement



This was done in a lab, we titrated 0.2M NaOH with an unknown concentration of acetic acid.
I've used excel to graph my first derivative of the data.

Homework Equations


(change in pH)/(Change in volume)

The Attempt at a Solution


My professor talked about drawing two trend lines, one from the left and the other from the right, and wherever they intersected, would be the equivalence volume. I'm just wondering if My trend lines should go through those two points at the top? I remember him saying not to force the lines to intersect at the highest point. But isn't it true that the equivalence point will have the largest slope?

Anyway, to me, the equivalence point volume looks to be around 19.9 mL

Did I do this right?
 

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crimsonn said:
My professor talked about drawing two trend lines, one from the left and the other from the right, and wherever they intersected, would be the equivalence volume. I'm just wondering if My trend lines should go through those two points at the top? I remember him saying not to force the lines to intersect at the highest point. But isn't it true that the equivalence point will have the largest slope?
In a perfect world, the equivalence point would have the highest slope. But since all your measurements have some degree of inaccuracy (and slope measurements in particular can be very inaccurate), the equivalence point might not correspond exactly to your highest slope point. Don't force your lines to go right through the top points, but don't ignore them. It would be best if you can choose trend lines that come fairly close to all the points.

Anyway, to me, the equivalence point volume looks to be around 19.9 mL

Did I do this right?
I would think somewhat to the right of 19.9, but I understand how you got that. I think you have the right idea.
 
Alright, thank you -- the part about whether to draw them through the top two points was the most confusing. I printed it out and drew the trend lines, and I agree that's its more like 19.97mL.
 

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