1. The problem statement, all variables and given/known data A bungee jumper of mass m=70 kg is riding a bungee cord with spring constant k=50 N/m. Its unstretched length is L=9.0 m. What is the amplitude of the jumper's oscillation? m=70 kg k=50 N/m L=9 m 2. Relevant equations mg(L+x)=(1/2)kx^2 x(t)=Bcos(omega(t)+alpha) omega = (k/m)^(1/2) 3. The attempt at a solution (70)(9.8)(9+x) = (1/2)(50)x^2 25x^2 - 686x - 6174 = 0 x = 34.58 (L+x)/2 = (9+34.58)/2 = 21.79 m I'm not really sure how to use the equation for simple harmonic motion to determine the amplitude, but shouldn't the amplitude just be (L+x)/2 given that air friction is negligible and total energy is conserved?