Nessary and sufficient condition for homomorphism to be isomorphism.

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SUMMARY

The necessary and sufficient condition for a homomorphism f from a group G to a group G' with kernel K to be an isomorphism is that the kernel K must equal the identity element {e}. The discussion highlights that while it can be proven that f is injective (one-to-one), the challenge lies in demonstrating that f is surjective (onto). It is established that if Ker(f) = {e}, then f is injective, but the assertion that f is an isomorphism is not universally valid.

PREREQUISITES
  • Understanding of group theory concepts, specifically homomorphisms and isomorphisms.
  • Familiarity with the definitions of kernels in the context of group mappings.
  • Knowledge of injective and surjective functions.
  • Basic proof techniques in abstract algebra.
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  • Study the properties of group homomorphisms in detail.
  • Learn about the implications of the First Isomorphism Theorem in group theory.
  • Explore examples of groups where homomorphisms are not isomorphisms.
  • Investigate the conditions under which a homomorphism can be proven to be surjective.
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Mathematicians, students of abstract algebra, and anyone studying group theory who seeks to deepen their understanding of homomorphisms and isomorphisms.

AAQIB IQBAL
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The necessary and sufficient condition for homomorphisim f of a group G into a group G' with kernel K to be isomorphism of G into G' is that k={e}
... THOUGH I AM ABLE TO PROVE THAT f IS ONE-ONE AND f IS HOMOMORPHISM (in converse part) BUT CAN'T GET ANY IDEA TO PROVE THAT f IS ONTO.
PLEASE HELP ME IN THIS REGARD
 
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That Ker(f)={e} is a necessary and sufficient condition for f to be injective.
You won't be able to prove that f is an isomorphism, because it is false in general.
 

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