The discussion revolves around determining the net force acting on a ping-pong ball when a paddle exerts a force at a specific angle. The problem involves concepts from mechanics, particularly the analysis of forces and vector addition.
There is an ongoing exploration of the correct approach to calculating the net force, with some participants providing alternative calculations and questioning the initial method. Guidance on the importance of vector addition and free body diagrams has been offered, indicating a productive direction in the discussion.
Some participants express uncertainty about their understanding of vector addition and the proper setup for analyzing forces, highlighting a potential gap in foundational knowledge that may affect their ability to solve the problem.
What's the logic behind your calculation?bbbbb said:Homework Statement:: A ping-pong ball has a weight of 0.50 N. While in contact with a paddle the paddle exerts a force of 7.8 N at 29° above the horizontal.
Relevant Equations:: Determine the net force acting on the ball at this instant.
w= 0.50N, Fn= 7.8N, angle= 29
Fnet= Fn*fd* costheta
= 7.8*0.50*cos(29
= 3.41
is my answer correct
3.41 cows? No, that's not even a force. How could it be correct?bbbbb said:Fnet= Fn*fd* costheta
= 7.8*0.50*cos(29
= 3.41
is my answer correct
I cannot think of any situation where it would make sense to multiply two forces.bbbbb said:Homework Statement:: A ping-pong ball has a weight of 0.50 N. While in contact with a paddle the paddle exerts a force of 7.8 N at 29° above the horizontal.
Relevant Equations:: Determine the net force acting on the ball at this instant.
w= 0.50N, Fn= 7.8N, angle= 29
Fnet= Fn*fd* costheta
= 7.8*0.50*cos(29
= 3.41
is my answer correct
Is that yes you have drawn a FBD? If so, please try to post it.bbbbb said:I do not know how to add forces vectorially?
Yes but I am not sure if it's correct.
Here's an approximate answer. We have a force of ##7.8N## and a force of ##0.5N##, which is small compared to the first. The answer should be close to ##7.8N## in a direction not much different from the direction of the larger force. The answer can't be ##3.41N## or anything like that.bbbbb said:We have two forces acting on the ball.
the force of gravity, there is no component is the x direction and all of the force is in the negative x direction
i will do the components of both using fcosθ for the x- component and fsinθ for the y-component
That looks a lot better!bbbbb said:For the Fnet I got 7.57N and the angle has 25.7