What's the logic behind your calculation?bbbbb said:Homework Statement:: A ping-pong ball has a weight of 0.50 N. While in contact with a paddle the paddle exerts a force of 7.8 N at 29° above the horizontal.
Relevant Equations:: Determine the net force acting on the ball at this instant.
w= 0.50N, Fn= 7.8N, angle= 29
Fnet= Fn*fd* costheta
= 7.8*0.50*cos(29
= 3.41
is my answer correct
3.41 cows? No, that's not even a force. How could it be correct?bbbbb said:Fnet= Fn*fd* costheta
= 7.8*0.50*cos(29
= 3.41
is my answer correct
I cannot think of any situation where it would make sense to multiply two forces.bbbbb said:Homework Statement:: A ping-pong ball has a weight of 0.50 N. While in contact with a paddle the paddle exerts a force of 7.8 N at 29° above the horizontal.
Relevant Equations:: Determine the net force acting on the ball at this instant.
w= 0.50N, Fn= 7.8N, angle= 29
Fnet= Fn*fd* costheta
= 7.8*0.50*cos(29
= 3.41
is my answer correct
Is that yes you have drawn a FBD? If so, please try to post it.bbbbb said:I do not know how to add forces vectorially?
Yes but I am not sure if it's correct.
Here's an approximate answer. We have a force of ##7.8N## and a force of ##0.5N##, which is small compared to the first. The answer should be close to ##7.8N## in a direction not much different from the direction of the larger force. The answer can't be ##3.41N## or anything like that.bbbbb said:We have two forces acting on the ball.
the force of gravity, there is no component is the x direction and all of the force is in the negative x direction
i will do the components of both using fcosθ for the x- component and fsinθ for the y-component
That looks a lot better!bbbbb said:For the Fnet I got 7.57N and the angle has 25.7
Net force is the overall force acting on an object, taking into account all the individual forces acting on it.
Net force is calculated by adding up all the individual forces acting on an object, taking into account their direction and magnitude.
The net force acting on a ping-pong ball will determine its acceleration and therefore its motion. If the net force is zero, the ball will remain at rest or continue moving at a constant velocity. If the net force is non-zero, the ball will accelerate in the direction of the net force.
The net force acting on a ping-pong ball can be affected by factors such as air resistance, gravity, and any external forces applied to the ball.
If the ping-pong ball is in motion, the net force acting on it can change if there are any changes in the individual forces acting on it. For example, if the ball encounters air resistance, the net force will decrease and the ball's acceleration will also decrease.