Net Force & Kinetic Energy: Does More Work Occur?

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SUMMARY

The discussion centers on the relationship between net force and work done during the acceleration of a particle whose speed doubles twice due to an external force. The work-energy theorem is crucial for understanding this relationship, specifically the equations U_{0,1} and U_{1,2}, which represent the work done during each speed increment. The conclusion is that the net force does more work during the second doubling of speed, as greater force is required to achieve the increased kinetic energy. The relevant equation for this analysis is E = 1/2 mv², which relates kinetic energy to work done.

PREREQUISITES
  • Understanding of the work-energy theorem
  • Familiarity with kinetic energy equations, specifically E = 1/2 mv²
  • Basic knowledge of net force and its relationship to acceleration
  • Ability to manipulate algebraic expressions to compare work done
NEXT STEPS
  • Study the work-energy theorem in detail
  • Learn how to derive work done from force and displacement
  • Explore examples of kinetic energy changes in physics problems
  • Investigate the implications of net force on acceleration and work
USEFUL FOR

Students studying physics, particularly those focusing on mechanics, as well as educators looking to clarify concepts of work and kinetic energy in relation to net force.

clarkandlarry
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Homework Statement


The speed of a particle doubles and then doubles again because a net external force acts on it. Does the net force do more work during the first or the second doubling? Justify your answer.

Homework Equations


I'm not sure, but i think E = 1/2 mv(squared)


The Attempt at a Solution



Im pretty sure this has something to do with kinetic energy, but the question is asking about the net force doing work. How do I incorporate force into this?
 
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use the work/kinetic-energy theorem
 
were you given any values? like mass...etc but i suspect the 2nd doubling because it would require a greater force to accelerate the particle even more than it has already been.
 
The question asks for how much work the force does. The specifics of the force don't matter, the only thing you want to find is how much work that force does.

Let U_{0,1} represent the work done by the force taking it from the initial speed to double the initial speed.
Let U_{1,2} represent the work done by the force in taking the particle from double the initial speed to quadruple the initial speed.

To compare U_{0,1} and U_{1,2}, you have to get them both in terms of the same variables. So how can you do this?
 
I'm not exactly sure how to do that. I think it has something to do with E = 1/2 mv(squared), but that deals with energy and not work. Is this the equation that I should be using when getting U0,1 and U1,2 in terms of the same variables?
 

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