Net Ionic Equation for the Reaction of Al(OH)3 and HCl

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SUMMARY

The net ionic equation for the reaction of aluminum hydroxide, Al(OH)3(s), with hydrochloric acid, HCl(aq), is represented as Al(OH)3(s) + 3H+(aq) → Al3+(aq) + 3H2O(l). Chloride ions (Cl-) are identified as the spectator ions in this reaction. The dissociation of Al(OH)3 is not applicable since it is presented in solid form, and thus does not dissociate in the equation. The correct balancing of the equation confirms the formation of aluminum ions and water as products.

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What is the net ionic equation of Al(OH)3(s)+3HCl(aq)=AlCl3(aq)+3H20

The answer a got was
Cl is the only spectator ion
Al3+ +3OH3- +3H3+ = Al3+ +3H2O
 
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DRC12 said:
Al3+ +3OH3-

You were told Al(OH)3(s)
 
I was given Al(OH)3(s)+HCl(aq)
then solved and balanced the equation as Al(OH)3(s)+3HCl(aq)=AlCl3(aq)+3H2O(l)
and I know that's correct I just can't figure out the net ionic equation and I'm not entirely sure what the spectator ions are but I'm pretty positive the only ones Cl
 
You are right about spectators, but you are wrong about Al(OH)3 being dissociated. It is given as Al(OH)3(s) for a reason.
 
So now i have it as Al(OH)3(s)+3H3+(aq)=3H2O(l)+Al3-(aq)

thats still not right but is that what you meant by being given Al(OH)3(s)?
 
Equation is so off my eyes hurt from looking, but you are on the right track now. Just half of the substances you listed don't exist.
 

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