Net Ionic Equation of Four Solutions

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SUMMARY

The net ionic equation for the reaction between sodium acetate (NaC2H3O3), barium chloride (BaCl2), ammonium nitrate (NH4NO3), and potassium chromate (K2CrO4) is Na+ + C2H3O3- + CrO42- → Na2CrO4(s) + H2O(l) + CO2(g). The driving forces of the reaction include the formation of sodium chromate, water, and carbon dioxide. The key to solving such problems lies in identifying spectator ions and applying solubility rules effectively.

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The problem statement

The solutions of ##NaC_2H_3O_3 + BaCl_2 +NH_4NO_3 + K_2CrO_4## are mixed together.

1. Write the Net Ionic Equation.

2. What is the driving force of the reaction?

The attempt

I'm not sure how to solve for the net ionic equation without a balanced equation. My professor showed us a way that involves only finding the ions and discarding the unneeded ones, but I haven't yet grasped the concept.


As of now, I have the following net ionic equation: $$Na{_{}}^{+}+C_2H_3O_3{_{}}^{-}+CrO_4{_{}}^{2-}\rightarrow Na_2CrO_{4(s)}+H_2O_{(l)}+CO_{2(g)}$$

Assuming this NIE is correct (I'm sure it isn't), then the driving forces would be all three products.

Any insight into the proper approach to this and similar problems would be greatly appreciated.
 
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Hint: think about solubility rules (sodium chromate is well soluble, so it is not a product here).

Most of the ions are just spectators.
 

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