Net Ionic Equations: NaCl + AgNO3 Reaction

[b.barkey]

Homework Statement

So the question is:

Enter the net ionic equation for the reaction of aqueous sodium chloride with aqueous silver nitrate.

Homework Equations

So i know that the first part of the equation is:
Na(ClO2)aq+Ag(NO3)aq --> i have no clue what should go here.
Please help

The Attempt at a Solution

and i don't ebern know how to attempt this problem... i tried:
Ag(aq) --> (ClO2)s
because this is what would change but it is saying it is not right.

 

[Borek]

NaClO₂ is not sodium chloride.

Start writing both compounds in ionic form, the way they dissociate in the solution. Don't ignore charges.

--

 

[b.barkey]

NaClO₂ is not sodium chloride.

Start writing both compounds in ionic form, the way they dissociate in the solution. Don't ignore charges.

--
www.titrations.info, www.chemistry-quizzes.info, www.ph-meter.info

OH WAIT! Sodium Chloride is just NaCl.

So it would be:

Na⁺+Cl⁺+Ag+NO₃^-

 

[Borek]

Close, just add correct charge to Ag.

Do you have any idea what can happen when you mix these salts? Hint: answer lies in the solubility rules.

 

[b.barkey]

Close, just add correct charge to Ag.

Do you have any idea what can happen when you mix these salts? Hint: answer lies in the solubility rules.

The Charge on Ag is a + right but my professor said something about in the Net ionic equation how all the reactents are not in it. so i was wondering how i would write the end equation... would it be:

Ag⁺_(aq) --> Cl^-_(s) or something like that..

 

[Borek]

Try to answer my question: what will happen in the solution?

--

 

[b.barkey]

Try to answer my question: what will happen in the solution?

--
www.titrations.info, www.chemistry-quizzes.info, www.ph-meter.info

the soluble ployatomic ion NO₃ would attach to the Na and the Ag would attach to the Cl and the AgCl would become a solid while the Na(NO₃) would still be aq... right?

 

[Borek]

Yes and no. You are right about AgCl precipitating from the solution and becoming solid, you are wrong about NO₃^- attaching to Na⁺ - they will just float in the solution, they aren't called spectators without a reason.

Now you should be able to write full ionic equation and cancel out spectators.