Net work problem with F cos theta

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Homework Help Overview

The problem involves analyzing the net work done on a 5.0 kg block moving along a flat horizontal surface, based on a graph representing the component of force (Fcos(theta)) over distance (s). The original poster seeks clarification on the meaning of the graph and the values for theta.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the relationship between the area under the graph and the work done, with some attempting to derive acceleration and final speed using kinematic equations. Questions arise regarding the interpretation of the graph's y-values and the assignment of theta.

Discussion Status

The discussion is active, with participants providing insights into the relationship between force, acceleration, and work. Some guidance has been offered regarding the calculation of work and acceleration, but there is no explicit consensus on the interpretation of the graph or the correctness of the calculations presented.

Contextual Notes

Participants are navigating potential ambiguities in the problem setup, particularly concerning the graph's representation and the values for theta. The original poster expresses uncertainty about these aspects, indicating a need for further clarification.

loganblacke
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Homework Statement


The graph below shows the component (Fcos(theta)) of the net force that acts on a 5.0 kg block as it moves along a flat horizontal surface. Find (a) the net work done on the block and (b) the final speed of the block if it starts from rest at s = 0.

The graph shows Fcos(theta)(N) as the y-axis and s (meters) as the x-axis. The coordinates are (0,0), (1,0), (1,2), (4,2), (4,-2), (6,-2), (6,0), (8,0), connected by straight lines in that order.


Homework Equations



Work=Force*Distance*cos(theta)

The Attempt at a Solution



I don't understand what the y value represents or what values to assign for theta. Please help!
 
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Work = Force x cos[tex]\Theta[/tex] x distance
This is the area under the given graph between Fcos[tex]\Theta[/tex] and s
 
Fcos[tex]\Theta[/tex] is the force acting in the direction of the motion of the body.
The acceleration of the body in the direction of motion can be calculated as
Force = mass x acceleration
After finding acceleration use
vf2 = vi2 + 2ax
 
Last edited:
A=.25/5.0=.05 m/s

Vf=sqrt(2*.05*8)=.8944 m/s^2

Thank you for your help!
 
Thank you for giving new problem to me.:smile:
Is the answer correct?
 

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