Force Applied at an Angle to an Object on Frictionless Surface

Click For Summary
SUMMARY

The discussion centers on calculating the acceleration of a block on a frictionless surface when a force is applied at an angle. Given a force (F) of 20 N and a mass (M) of 5.0 kg, the correct method involves resolving the force into its horizontal component using F_{x} = Fcos(θ), where θ is 30°. The resulting acceleration is calculated as a_{x} = Fcos(θ)/m, leading to an acceleration of 7.5 m/s², correcting an initial miscalculation of 3.46 m/s² due to overlooking the total force applied.

PREREQUISITES
  • Understanding of Newton's Second Law (F=ma)
  • Knowledge of vector components in physics
  • Familiarity with trigonometric functions, specifically cosine
  • Basic principles of motion on frictionless surfaces
NEXT STEPS
  • Study vector decomposition in physics problems
  • Learn about the implications of frictionless surfaces on motion
  • Explore advanced applications of Newton's laws in two dimensions
  • Practice problems involving forces at angles and their effects on acceleration
USEFUL FOR

This discussion is beneficial for physics students, educators, and anyone interested in understanding dynamics, particularly in scenarios involving forces and motion on frictionless surfaces.

jpsmith394
Messages
2
Reaction score
0

Homework Statement


The horizontal surface on which the block slides is frictionless. If F = 20 N and M = 5.0 kg, what is the magnitude of the resulting acceleration of the block? The force is applied 30° to the horizontal.


Homework Equations


F=ma


The Attempt at a Solution


I began by ignoring the weight and normal force in the vertical axis (y-axis) because the surface is frictionless. Then my next step is to separate the force into compenets with F_{x}=Fcos\theta

Therefore:
ƩF_{x}=Fcos\theta = ma_{x}

So:
a_{x}=\frac{Fcos\theta}{m}

And using the given numbers I got a solution of 3.46\frac{m}{s^2}
But the online system I am using shows the correct answer as 7.5\frac{m}{s^2}
 

Attachments

  • Screen Shot 2013-09-28 at 6.19.51 PM.png
    Screen Shot 2013-09-28 at 6.19.51 PM.png
    12 KB · Views: 1,716
Last edited:
Physics news on Phys.org
hi jpsmith394! welcome to pf! :smile:

erm :redface: … you forgot the other F, in front! :wink:
 
tiny-tim said:
hi jpsmith394! welcome to pf! :smile:

erm :redface: … you forgot the other F, in front! :wink:

Oh gosh I see now, I was just stuck thinking it was just a single force

Thanks,
James
 

Similar threads

  • · Replies 41 ·
2
Replies
41
Views
4K
  • · Replies 8 ·
Replies
8
Views
1K
Replies
17
Views
4K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 12 ·
Replies
12
Views
3K
Replies
2
Views
2K
Replies
12
Views
3K
  • · Replies 14 ·
Replies
14
Views
3K
  • · Replies 10 ·
Replies
10
Views
6K
  • · Replies 18 ·
Replies
18
Views
2K