- #1
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- Homework Statement
- Mike the Mailman takes his oath seriously: "Neither snow, nor rain, nor heat, nor gloom of night stays these courageous couriers from the swift completion of their appointed rounds". Even though a blizzard is raging outside, he goes out to deliver the mail.
He makes four stages along his route:
First, he walks 40 meters North.
Next, he walks 53 meters East.
Then, he walks 42 meters at an angle of 30 degrees South of East.
Finally, he walks 80 meters at an angle of 10 degrees West of South.
The entire time he is outside, the wind pushes him with a force of 130 Newtons at at 36 degrees South of East,
How much work does the wind do to Mike over the course of his deliveries?
What is Mike's displacement from his original position? Express your answer in terms of vector components:
- Relevant Equations
- net work= force(distance)cos(theta)
Homework Statement: Mike the Mailman takes his oath seriously: "Neither snow, nor rain, nor heat, nor gloom of night stays these courageous couriers from the swift completion of their appointed rounds". Even though a blizzard is raging outside, he goes out to deliver the mail.
He makes four stages along his route:
First, he walks 40 meters North.
Next, he walks 53 meters East.
Then, he walks 42 meters at an angle of 30 degrees South of East.
Finally, he walks 80 meters at an angle of 10 degrees West of South.
The entire time he is outside, the wind pushes him with a force of 130 Newtons at at 36 degrees South of East,
How much work does the wind do to Mike over the course of his deliveries?
What is Mike's displacement from his original position? Express your answer in terms of vector components:
Homework Equations: net work= force(distance)cos(theta)
I initially tried to substitute distance=40+53+42+80. Force=130N and theta=36degree. The total work=(130N)(215m)cos(36)=22.6 * (10^3) J.
He makes four stages along his route:
First, he walks 40 meters North.
Next, he walks 53 meters East.
Then, he walks 42 meters at an angle of 30 degrees South of East.
Finally, he walks 80 meters at an angle of 10 degrees West of South.
The entire time he is outside, the wind pushes him with a force of 130 Newtons at at 36 degrees South of East,
How much work does the wind do to Mike over the course of his deliveries?
What is Mike's displacement from his original position? Express your answer in terms of vector components:
Homework Equations: net work= force(distance)cos(theta)
I initially tried to substitute distance=40+53+42+80. Force=130N and theta=36degree. The total work=(130N)(215m)cos(36)=22.6 * (10^3) J.