Network Analysis, Kirchhoff's Laws, changing current source to voltage

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SUMMARY

This discussion centers on the application of Kirchhoff's Laws in circuit analysis, specifically addressing the transformation of a current source into a voltage source. The user initially struggled with formulating equations involving the current source but received guidance on correctly identifying nodes and branches in the circuit. Key equations established include I1 + I2 + I3 = I(R3) and KVL for the loop being (-U3) + (U3 - U2) + (U2) = 0. The importance of consistent definitions and polarities in circuit equations was emphasized, leading to a successful resolution of the user's problem.

PREREQUISITES
  • Understanding of Kirchhoff's Current Law (KCL)
  • Familiarity with Kirchhoff's Voltage Law (KVL)
  • Basic knowledge of electrical circuit components (resistors, current sources, voltage sources)
  • Ability to formulate and solve linear equations
NEXT STEPS
  • Study the application of Kirchhoff's Laws in complex circuits
  • Learn about the transformation of current sources to voltage sources
  • Explore node voltage analysis techniques
  • Review circuit simulation tools such as LTspice or Multisim
USEFUL FOR

Electrical engineering students, circuit designers, and anyone involved in circuit analysis and design will benefit from this discussion.

Emo_Jesus
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Homework Statement
The voltage U1, U2 the current I3 and the resistors R1, R2, R3 are given.
a) Write down the equations needed to calculate U3 using Kirchhoffs Laws and Ohms Laws.
b) calculate U3 using the Network-equations
Relevant Equations
Kirchhoffs 1. and 2. Law, U = R*I
I tried setting up 4 equations using Kirchoffs laws, but the current source is throwing me off, as i dont know wether to include it in the loop, and if it would be smart to transform it into a voltage source.
The equations i have so far are:
I1 + I2 + I3 = I(R3)
I(R3) = I1 + I4
I4 = I2 + I3
U1 = U(R1) + U3

I(R3) being the current through R3, I2 through R2, R1 through R1, and I4 being the one going "right" at the knot under R3

Screenshot_2.png


Any help is highly appreciated, thank you :)
 
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Emo_Jesus said:
The equations i have so far are:
I1 + I2 + I3 = I(R3)
I(R3) = I1 + I4
I4 = I2 + I3
U1 = U(R1) + U3

I(R3) being the current through R3, I2 through R2, R1 through R1, and I4 being the one going "right" at the knot under R3
This is the wrong approach.

Nodes and branches in the circuit must be identified correctly.
What is a node in an electrical circuit? What is a branch in an electrical circuit?

All linearly independent equations written by using the first and the second Kirchhoff’s laws must be included.
How many linearly independent equations can be written by using the first Kirchhoff’s law? How many linearly independent equations can be written by using the second Kirchhoff’s law?
 
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Yes, you include it in the loop for KVL, sort of. It doesn't matter what the circuit element is for KVL you are simply defining the voltages across each and adding them up.

So KVL for the right most loop (clockwise) is simply ##(-U_3) + (U_3 - U_2) + (U_2) = 0##.
You can then substitute using the circuit element definitions. For example ##(U_3-U_2)=R_2 I_{R2} ##.
You don't have to substitute anything for ##U_2##, it is a known value or independent variable.
You can't substitute anything for ##U_3## since the current source circuit element doesn't define it's own voltage, that is one of the things you need to solve for.

KCL is similar, of course, but with nodes instead of loops.

Be very careful with your definitions and polarities. You must be consistent in all of the equations.
 
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Thank you both for the Help, i solved it now! :)
 
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