bhobba
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vanhees71 said:The KS theorem states that it doesn't make sense to assume that compatible observables have a certain value, if the system is not prepared in a common eigenstate of the representing operators of these observables. I don't see where this can be a problem for the MSI, which precisely states that such compatible observables can only have determined values when the system is prepared in a common eigenstate.
Could you point me to the problems Ballentine has stated about the KS theorem in context with the MSI? In his book "Quantum Mechanics, A Modern Development" I can't find any such statement, and the KS theorem is discussed there in the concluding chapter on Bell's inequality.
The KS theorem is not a problem for the MSI providing you do not assume it has the value prior to observation. However that is a very unnatural assumption. When the observation selects an outcome from the ensemble of similarly prepared systems with that outcome associated with it you would like to think it is revealing the value it has prior to observation - but you can't do that.
A number of books such as Hugh's - Structure And Interpretation of QM mention the issues the Ensemble interpretation has with the KS - I can dig up the page if you really want - but not now - feeling a bit tired. They claim it invalidates it - it doesn't - but the assumption you need to make to get around it is slightly unnatural - that's all - it can not be viewed as classical probabilities like say tossing a dice unless you invoke decoherence.
I did manage to find the following online:
http://books.google.com.au/books?id...&q=ballentine ensemble kochen specker&f=false
I too have Ballentines book and its not in there anywhere - I read it in some early paper he wrote on it but can't recall which one. But since then I think he realized it wasn't really an issue if you abandon viewing it like classical probabilities.
Thanks
Bill
