Newton-Raphson Method for Solving Tan(x) = x with 3 Iterations

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The discussion revolves around using the Newton-Raphson method to solve the equation tan(x) = x for a strut's buckling load. An initial approximation of x0 = 4.5 is provided, and the user derived the first derivative correctly. However, they are struggling to obtain a satisfactory value after three iterations, expecting to reach approximately 4.49340946. A suggestion is made to verify the results by calculating tan(x) - x to check how close the outcome is to zero. The conversation emphasizes the importance of validating the results to ensure accuracy in the iterative process.
Student2010
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Hi Please can somebody help


The equation governing the buckling load P of a strut with one end fixed and the other end simply supported is given by tan (Mu)L = (Mu)L where (Mu) = Sqrt (P/EI), L the length of the strut and EI the flexural rigidity of the strut.
By writing x = (Mu)L, solve the equation tan x = x using three iterations of the Newton-Raphson method, taking
an initial approximation x0 = 4.5



I got the equation for the first derivative to be
f(1)(x)= sec^2(x)-1

x1= x0 - (tan(x0)-x0)/(sec^2(x0)-1)

but i can't get a value out of the equation which seems right, when i carry on to the 3rd iteration it says i should get an answer of around 4.49340946


Would really appreciate help

Thank You
 
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Student2010 said:
but i can't get a value out of the equation which seems right, when i carry on to the 3rd iteration it says i should get an answer of around 4.49340946

What makes you think it isn't right? There is an easy way to verify. Calculate tan(x) - x and see how close to zero it is.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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