Attempted Part I & II Problems

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SUMMARY

The discussion centers on solving a two-part physics problem involving projectile motion. The primary challenge arises in part ii, where the absence of an air resistance term complicates the attainment of the x value derived in part i. Participants clarify that without air resistance, the problem simplifies to basic projectile motion principles. Additionally, it is emphasized that the constant term, ##c_2##, must be set to zero before integration to ensure valid solutions.

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Homework Statement
A bullet of mass m is shot vertically up with initial speed v0. It is subject to air resistance that is quadratic in speed (constant of proportionality c2).

i. What is the maximum height reached?

ii. What initial speed u0, would be necessary to reach the same maximum height in the absence of air resistance?

Express your answers in terms of c2, g, m, and v0.
Relevant Equations
For part i: m(dv/dt) = -c2(v^2) - mg
I have an attempted solution to part i here. I'm primarily having trouble with part ii since I don't see how the x found in part i can be attained if there's no air resistance term.
 

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theredbarronmvr said:
I'm primarily having trouble with part ii since I don't see how the x found in part i can be attained if there's no air resistance term.
If there is no air resistance, then it's a simple projectile motion problem.
 
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PeroK said:
If there is no air resistance, then it's a simple projectile motion problem.
Ahh of course, thank you! I was definitely overthinking it.
 
theredbarronmvr said:
I have an attempted solution to part i here. I'm primarily having trouble with part ii since I don't see how the x found in part i can be attained if there's no air resistance term.
In case you're wondering, when you evaluated the integral, you assumed ##c_2 \ne 0##, so it isn't valid to set ##c_2=0## in the expression you derived. (I assume that's the difficulty you were running into.) You have to set ##c_2## to 0 before you integrate.
 
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