Newton's laws. Force and Tension help

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SUMMARY

The discussion focuses on applying Newton's laws to calculate forces and tensions in two scenarios involving a jet engine and a FedEx box. For the jet engine, the force on each bolt when the plane is stationary is calculated to be 4638.7 N. During turbulence, with an upward acceleration of 2.1 m/s², the force on each bolt is incorrectly calculated as 3644.7 N, indicating a misunderstanding of how to apply the acceleration to the total force. The second problem involves determining the tension in a cord connecting two boxes on a frictionless plane, requiring the application of free body diagrams and Newton's second law.

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  • Understanding of Newton's laws of motion
  • Familiarity with free body diagrams
  • Knowledge of basic physics equations, specifically Fnet = m * a
  • Ability to perform calculations involving forces, mass, and acceleration
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  • Review the application of Newton's second law in dynamic systems
  • Study the concept of free body diagrams for complex systems
  • Learn how to calculate net forces during acceleration scenarios
  • Explore tension calculations in pulley systems with multiple masses
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Homework Statement


A 1420 kg jet engine is fastened to the fuselage of a passenger jet by just three bolts (this is the usual practice). Assume that each bolt supports one-third of the load.

(a) Calculate the force on each bolt as the plane waits on line for clearance to take off.

(b) During flight, the plane encounters turbulence, which suddenly imparts an upward vertical acceleration of 2.1 m/s2 to the plane. Calculate the force on each bolt now.


My second question is this...
2. A force F of magnitude 10 N is applied to a FedEx box of mass m2 = 1.0 kg. The force is directed up a plane tilted by θ = 37°. The box is connected by a cord to a UPS box of mass 2.5 kg on the floor. The floor, plane, and pulley are frictionless, and the masses of the pulley and cord are negligible. What is the tension in the cord?

hrw7_5-66.gif


Homework Equations



Fnet = m * a

I think these equations work, not sure though.
F-T-m2*g*sin37= m2 * a1
T= m1 * a2
(F-T- m2 * g * sin37)/m2= T/m1

The Attempt at a Solution



1. (a). I got this one correct, it is 4638.7 N.

(b). This one I thought I did correct but it keeps telling me I am doing it wrong. I did (1420 * 9.80) - (1420 * 2.1) = 10934. Then I devided 10934 by 3 and got 3644.7 but it keeps saying that is wrong.

As for the second question, I wasn't sure how to work those problems as those equations require the acceleration, and I wasn't sure how to get that.

I tried to do 2.5*cos37, but then I though that you couldn't do that with the weight. I am really stuck on this one.
 

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for question 1 part b:

there is an upward vertical acceleration =2.1 m/s*s .. What you have done is assuming that this acceleration is divided into 3 parts, try applying this acceleration (2.1) to each part , what answer you will end up??


As for question 2, I suggest you start by drawing free body diagrams for m1 and m2 , and see what forces act on each of them by applying Newtons 2nd law ..
 

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