- #1

Ithilrandir

- 82

- 3

- Homework Statement
- In the system shown in Fig. 5-5, M1 slides without friction on the inclined plane. Θ=30°, M1 = 400g, M2 = 200g. Find the acceleration a of M2 and the tension T in the cords.

- Relevant Equations
- ...

First I determined the direction the masses will be traveling by comparing the change in potential energy, so when M2 rises by Δy, M1 drops by Δy. Potential energy decreases when M1 drops and M2 goes up.

Tension force for string pulling against M1= 400 x gsin30°, and since there are two strings pulling against the pulley, force caused by the lower pulley = 400g.

Tension force due to M2= 200g.

Net force=400g-200g=200g=0.200 x 9.81= 1.962N

Acceleration = 1.962/(0.400+0.200)=3.27 m s^-1

T=1.962N.

My answer feels off, so I checked the answer, and the answer's acceleration is g/9= 1.09, T=2.17782N

Could anyone help point my mistakes?

Tension force for string pulling against M1= 400 x gsin30°, and since there are two strings pulling against the pulley, force caused by the lower pulley = 400g.

Tension force due to M2= 200g.

Net force=400g-200g=200g=0.200 x 9.81= 1.962N

Acceleration = 1.962/(0.400+0.200)=3.27 m s^-1

T=1.962N.

My answer feels off, so I checked the answer, and the answer's acceleration is g/9= 1.09, T=2.17782N

Could anyone help point my mistakes?