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If 2T1 - T2=ma and m=0 then...?Ithilrandir said:3. Resultant force = 2T1 - T2
4. If the pulley has negligible mass, F = ma shouldn't be calculable?
If 2T1 - T2=ma and m=0 then...?Ithilrandir said:3. Resultant force = 2T1 - T2
4. If the pulley has negligible mass, F = ma shouldn't be calculable?
Yes!Ithilrandir said:2T1 = T2?
Thanks, I solved the answer. I was under the impression that the pulley accelerates with force = ma and trying to solve it abstractly that way.haruspex said:Yes!