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If 2T1 - T2=ma and m=0 then...?Ithilrandir said:3. Resultant force = 2T1 - T2
4. If the pulley has negligible mass, F = ma shouldn't be calculable?
The discussion revolves around the dynamics of an Atwood machine involving two masses, M1 and M2, connected by a cord over a pulley. Participants explore the relationship between tension in the cords, the effect of angles, and the acceleration of the masses as one rises and the other descends.
Participants are actively engaging with the problem, raising questions about their calculations and the assumptions made. Some have offered insights into the relationships between the forces and tensions, while others are reconsidering their approaches based on feedback. There is no explicit consensus on the correct method or outcome yet.
Some participants note the importance of understanding the Atwood machine concept and the implications of acceleration in relation to the forces acting on the masses. There is also mention of the need to clarify the role of the pulley and the geometry involved in the problem.
If 2T1 - T2=ma and m=0 then...?Ithilrandir said:3. Resultant force = 2T1 - T2
4. If the pulley has negligible mass, F = ma shouldn't be calculable?
Yes!Ithilrandir said:2T1 = T2?
Thanks, I solved the answer. I was under the impression that the pulley accelerates with force = ma and trying to solve it abstractly that way.haruspex said:Yes!