Newton's Laws of Motion PROBLEM

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SUMMARY

The discussion focuses on solving a physics problem involving Newton's Laws of Motion, specifically calculating the horizontal acceleration of a lawn mower with a mass of 20 kg. A force of 150 N is applied at an angle of 60 degrees, and the coefficient of kinetic friction is 0.20. The normal force (Fn) is calculated as 326 N, which is essential for determining the friction force. The friction force is then used to find the net force acting on the mower, allowing for the calculation of horizontal acceleration using F=ma.

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  • Understanding of Newton's Laws of Motion
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  • Familiarity with friction coefficients and their application
  • Basic algebra for solving equations
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[SOLVED] Newton's Laws of Motion PROBLEM!

A gardener pushes down along the handle of a lawn mower of 20 kg mass with a force of 150 N. The handle makes an angle of 60 degrees with the ground. Calculate the horizontal acceleration of the mower if the coefficient of kinetic friction between its wheels and the gound is 0.20.


Attempt:
I've gotten this equation so far but I'm confused on what to do next!

Fn = mg + FaSin[tex]\theta[/tex]

= 20(9.8) + 150sin60

Fn = 326 N <---?
 
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Fn is, I presume, the component of force normal to the ground. You calculated that in order to be able to find the friction force didn't you? The friction force is the coefficient of kinetic friction (0.20) multiplied by Fn. You will also want to find the component of foce parallel to the ground. That, minus the friction force, you put into "F= ma"
 

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