- #1

chroncile

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## Homework Statement

A proud homeowner is out mowing their lawn. If the force of friction on the mower is 50.0 N and it is accelerating forward at 0.15 m/s

^{2}, what is the magnitude of the applied force if the owner is pushing on the handle of the mower at an angle of 70 below the horizontal? How big is the normal force acting on the lawnmower? The mass of the lawnmower is 11 kg.

## Homework Equations

Fnet = Fapp + Ff

Fnet = ma

Fg = mg

## The Attempt at a Solution

Fnet = Fapp + Ff

0.15 * 11 = Fapp

_{x}+ (-50.0)

1.65 + 50.0 = Fapp

_{x}

Fapp

_{x}= 51.65 N

Fapp

_{y}= 51.65 * tan(70) = 142 N

Fapp = SquareRoot (51.65

^{2}+ 142

^{2})

Fapp = 151 N

0 = Fapp

_{y}+ Fn + Fg

0 = 142 + Fn + 11*9.8

Fn = -250 N

Correct answers are:

Fapp = 151 N

Fn = 156 N

How would you get the normal force?