- #1

flawlessbrown

- 12

- 0

## Homework Statement

A gardener pushes down on the handle of a lawnmover, applying a force of 250N. The handle is inclined at an angle 45* to the horizontal. If the coefficient of the kinetic friction between the wheels of the lawnmower and the ground is 0.40, what is the acceleration of the 20-kg lawnmower?

## Homework Equations

Fnet=0=Fn+Fsin45-Fg

Fn=mg-FSin45

a=(Fx-Ff)/m

Fnet=ma

Ff=(UkFn) Uk=coefficient of friction miew? or meiu

## The Attempt at a Solution

Answer is 1.38m/s^2

Last edited: