# Need help Newtons laws two diemnsions (vertical plane)

## Homework Statement

A gardener pushes down on the handle of a lawnmover, applying a force of 250N. The handle is inclined at an angle 45* to the horizontal. If the coefficient of the kinetic friction between the wheels of the lawnmower and the ground is 0.40, what is the acceleration of the 20-kg lawnmower?

## Homework Equations

Fnet=0=Fn+Fsin45-Fg
Fn=mg-FSin45
a=(Fx-Ff)/m
Fnet=ma
Ff=(UkFn) Uk=coefficient of friction miew? or meiu

## The Attempt at a Solution

Last edited:

PhanthomJay
Homework Helper
Gold Member
Your first equation applies on the y direction, but you have a signage error. The weight acts down and so does the vertical component of the applied force. The normal force acts up ; solve for it. Also, be sure to identify the horizontal component of the applied force, Fx.

Your first equation applies on the y direction, but you have a signage error. The weight acts down and so does the vertical component of the applied force. The normal force acts up ; solve for it. Also, be sure to identify the horizontal component of the applied force, Fx.
so are you saying my expression should be Fn= -mg+Fsin45 ?

PhanthomJay