Newtons laws of universal gravitation

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Queen B
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Homework Statement


its 3.8 x 10^8 from Earth's core to the lunar's core
calculate the gravitational attraction exerted by Earth on the moon

Homework Equations


ag = GM/ r^2
G= 6.67 x 10^-11
M of earth= 5.98 x 10^24 ... r= 6.37 x 10^6
M of moon= 7.36 x 10^22 ... r= 1.74 X 10^6


The Attempt at a Solution


ag = ( 6.67 x 10^-11)( 7.36 x 10^22) / ( 6.37 x 10^6) ^2 = 0.12 N
I'm not sure if I'm right or not, I am just really confused as to where I plug in the numbers
 
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Queen B said:

Homework Statement


its 3.8 x 10^8 from Earth's core to the lunar's core
calculate the gravitational attraction exerted by Earth on the moon

Homework Equations


ag = GM/ r^2
G= 6.67 x 10^-11
M of earth= 5.98 x 10^24 ... r= 6.37 x 10^6
M of moon= 7.36 x 10^22 ... r= 1.74 X 10^6


The Attempt at a Solution


ag = ( 6.67 x 10^-11)( 7.36 x 10^22) / ( 6.37 x 10^6) ^2 = 0.12 N
I'm not sure if I'm right or not, I am just really confused as to where I plug in the numbers

When the question asks for the gravitational attraction it is asking for the force. You are calculating the acceleration (toward the centre of mass of the earth-moon system). The units would m/sec^2.

Other than that your answer appears to be correct. Welcome to PF by the way!

AM
 
Andrew Mason said:
When the question asks for the gravitational attraction it is asking for the force. You are calculating the acceleration (toward the centre of mass of the earth-moon system). The units would m/sec^2.

Other than that your answer appears to be correct. Welcome to PF by the way!

AM

But how would I calculate the force? And thank you.
 
F=ma, ok i see now but what mass would i use?
 
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