The steel ball is suspended from the accelerating frame by the two cords A and B. The angles (they are on the inside) are both 60 degrees.
Determine the acceleration of the frame which will cause the tension in A to be twice that in B. The acceleration is going to the right and the cord A is to the right of the moving frame.
Provide your answer in m/s/s with one decimal point accuracy
I want to know how to relate the forces on the inside of the accelerating frame to the accelerating frame itself.
The Attempt at a Solution
Thus far, I have drawn free body diagrams to the inside cords and steel ball. I broke down the components of cord A and B and found the x-coordinate of cord A to be Acos60 and y-coordinate of Asin60. I got these same results for cord B. Combining knowns I've determined both cords tension to be .87w where w equals the weight of the ball. I'm now stuck and don't know how this relates to the moving frame where I think the force is F=ma(of x) and a(of x)=F/m...Have I screwed up this entire problem?