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Nice math proof arctan(x)+arctan(1/x)=sign(x)pi/2

  1. Feb 5, 2009 #1
    Hi everybody, im new here and like physics very much
    I came across a post here about the proof for: arctan(x)+arctan(1/x)=sign(x)pi/2
    and wanted to share a differnt point of view (not completely scientific but could be aranged)
    OK. so the proof uses the Brewster angle in Optics.

    Brewster summarization:
    Brewster's angle is the angle where the wave is completely transfered from
    one matter (n_1) to another (n_2): tan(Theta_B)=n_2/n_1
    =>Theta_B=arctan(n_2/n_1)
    Now Imagine two waves one from n_1 hitting the surface at brewster angle and another on the other side of the surface at it's own brewster angle (the fraction of n's is inverse)
    it is pretty "clear" (unexplained here but true) that the first one will continue at the same angle as the second one hit the surface and therefore according to snell's law the angle between the first hitting wave and it's transfered wave will be pi/2. (same for the second wave)
    ===>arctan(x)+arctan(1/x)=sign(x)pi/2
    Yeah, I know its not complete and it does not work for negative x's (no negative refractive index as far as I know) but it's a little 'out of the box'
     
  2. jcsd
  3. Feb 6, 2009 #2
    Hi John,

    I'm new here, too. I like the idea of using an application to prove a pure math theorem, but I don't think I have a very good visual of your explanation. Can you post a diagram so I can see what's going on?
     
  4. Feb 7, 2009 #3
    Here is a sketch:
    http://img9.imageshack.us/img9/3328/45971616gg3.jpg [Broken]

    Two different matters (refractive indexes n1 & n2)
    The xy plane is the border between matter 1 and 2.

    K1,2 are the wave vectors and ThetaB12,21 are the Brewster angles for waves from 1 to 2 and from 2 to 1 respectively.

    Now try and read the last post and see if it makes it any clearer.
    If not I don't mind trying again.
     
    Last edited by a moderator: May 4, 2017
  5. Feb 9, 2009 #4
    I'm afraid there are negative refractive indexes, now all you have to do is generalise it. :tongue2:

    http://en.wikipedia.org/wiki/Negative_refractive_index#Negative_refractive_index

     
  6. Feb 9, 2009 #5
    Yeah your right I forgot.

    In one of my courses (EM fields) we actually tried to build (theoretically) a matter made of little dielectric balls and calculated their properties in order to get a negative refractive index.
    negativerefraction.jpg

    And here is what it would look like: (the one on the right)
    445346a-i2.0.jpg

    By the way that is one of the ways they intend to build invisible cloaks where the EM waves detour the object
     
  7. Feb 9, 2009 #6
    I wonder if anyone would be interested in a proof in all cases?

    Never the less it is interesting. I always groan when my maths program throws out the signum function though. :eek:
     
  8. Feb 9, 2009 #7
    you prefer looking at it as a step function?:wink:
     
  9. Feb 9, 2009 #8
    Given a preference, not looking at it at all would be favourite. :smile:
     
  10. Aug 10, 2011 #9
    Hi there I noticed that you used the sign(x) function, I came across it the other day and had trouble trying to figure it out I asked some Math C teachers I know but they didn't know either, I am wondering if you could please explain it to me
     
  11. Aug 10, 2011 #10
    First of all I don't know if you noticed but the post is from two and a half years ago (quite some time).

    Now, if you want to know about the sign function an easy way to think of it is a funtion which is negative one on the left hand side of the axis and positive otherwise.
    In other words:
    if x<0 sign(x)= -1
    else sign(x)= +1

    if anymore explaining is needed i'd be more than happy to help though I am sure you could find a whole topic about it in Wiki

    Good luck
     
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