Node Voltage (is my answer correct )

Click For Summary
SUMMARY

The discussion centers on calculating node voltages V1, V2, V3, and V4 using Kirchhoff's Voltage Law (KVL) and the node voltage method. The correct values established are V1 = 6V and V4 = 16V, while V2 and V3 were initially miscalculated as negative values. The correct approach involves summing currents at each node and setting them equal to zero, leading to the equations: V2 = 16V and V3 = 0. The confusion arose from incorrect terms and arithmetic errors in the calculations.

PREREQUISITES
  • Understanding of Kirchhoff's Current Law (KCL)
  • Familiarity with node voltage analysis
  • Basic knowledge of circuit analysis techniques
  • Proficiency in solving linear equations
NEXT STEPS
  • Study the node voltage method in detail
  • Practice solving circuit equations using KCL
  • Learn about Kirchhoff's Voltage Law (KVL) applications
  • Explore circuit simulation software for verification of calculations
USEFUL FOR

Electrical engineering students, circuit designers, and anyone involved in analyzing electrical circuits using node voltage methods.

pokie_panda
Messages
35
Reaction score
0
http://www.flickr.com/photos/84781786@N03/7822251544/
Find the node VOLTAGE for V1,V2,V3,V4

Homework Equations


KVL

The Attempt at a Solution



V1 = 6V
V4= 16V
V2= V2/1.5k - 6/1.5k + V2/ 1k + V2/3.3k - V3/3.3k
6/1500 = V2/5.8k - V3/3.3k
V3 = V3/2.2k + V3 / 4.7k + V3/3.3k - V2/3.3k - 16/2200
16/2200 = - V2/3.3k + V3/ 10.2k

But I'm getting 2 negative answers
V2= -34.6 V V3= -32.9
 
Last edited by a moderator:
Physics news on Phys.org
pokie_panda said:
http://www.flickr.com/photos/84781786@N03/7822251544/
Find the node VOLTAGE for V1,V2,V3,V4

Homework Equations


KVL


The Attempt at a Solution



V1 = 6V
V4= 16V
V2= V2/1.5k - 6/1.5k + V2/ 1k + V2/3.3k - V3/3.3k
Why is that V2 = ? Surely you're forming a sum of currents at the node, which should yield a (zero) current?
6/1500 = V2/5.8k - V3/3.3k
How did you arrive at the V2/5.8k term?
V3 = V3/2.2k + V3 / 4.7k + V3/3.3k - V2/3.3k - 16/2200
16/2200 = - V2/3.3k + V3/ 10.2k
Again, the "V3 =" doesn't make sense. Perhaps you're just being a tad sloppy with terminology? The "=" sign is reserved for use in equations. Did you mean to indicate that "This is the expression for node V3?"

Also again, can you explain how you arrived at the term V3/10.2k?
 
I agree with Gneill - Your equations are a bit off - I think you mean:

V1: V1 = 6V
V2: V2 = 16V
V3: 0 = V2 / 1.5k - V1 / 1.5k + V2 / 1.0k + V2 / 3.3k - V3 / 3.3k
V4: 0 = V3 / 3.3k - V2 / 3.3k + V3 / 4.7k + V3 / 2.2k - V4 / 2.2k

Note that using the node voltage method used Kirchov's Current Law which states that all the currents going into a node must equal zero. Using the node voltage method you are simply summing the currents into each node and setting them equal to zero - not V3 or V4.

If you solve these equations you will come up with the correct answer... it took me a couple tries - my arithmetic is rusty, I guess... but I think I just fat fingered a value into my calculator. I did finally arrive at the correct answer, which I verified with software.

Hope this helps.

Also note that:
V2 / 1.5k + V2 / 1.0k + V2 / 3.3k does NOT equal V2 / 5.8k
http://www.mathsisfun.com/fractions_addition.html
I think there was some confusion there as well which could have been the root of your negative number solution.

On the plus side - good for you for realizing there was no way the answer could be negative without a negative voltage source.
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K
Replies
1
Views
2K
Replies
7
Views
3K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 1 ·
Replies
1
Views
3K
Replies
3
Views
7K
  • · Replies 3 ·
Replies
3
Views
13K