Node Voltage Method: Solve for v0 in Circuit

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The discussion focuses on using the node-voltage method to find v0 in a circuit. The initial attempt included an incorrect reference node and equation setup, leading to confusion about the inclusion of current in a voltage calculation. After feedback, the user revised their equation to correctly account for the potential differences and currents in the circuit. The final solution for v0 was determined to be 4.00V after correcting the calculations. The conversation highlights the importance of accurately setting reference nodes and understanding circuit relationships in node-voltage analysis.
orangeincup
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Homework Statement



Use the node-voltage method to find v0 in the circuit below.

Homework Equations



i1+i2+...in=0
i=v/R

The Attempt at a Solution


So I set my reference node to the top of the middle line(above 25Ω)
Equation...
24V/(20+80)Ω+v0/25+.004A=0

Now I can solve for v0=(-.004-24/100 )* 25, v0=-6.1V

I think I did something wrong, I'm confused about a few things. How do I know where to take my reference node? Also, I'm solving for v0, yet I'm adding .004 amps to the answer. Since I'm solving for voltage, how is this possible?

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I do not see any figure.

ehild
 
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orangeincup said:

Homework Statement



Use the node-voltage method to find v0 in the circuit below.

Homework Equations



i1+i2+...in=0
i=v/R

The Attempt at a Solution


So I set my reference node to the top of the middle line(above 25Ω)
Equation...
24V/(20+80)Ω+v0/25+.004A=0

that is not correct. The current through the 20+80Ω resistors flows through the potential difference v0-24V.

ehild
 
Oh I see. I updated my solution:

(v0-24)/100+v0/25+0.004A=0

v0/100Ω+v0/25Ω=24V/100Ω-0.004A

0.05v0=.24A-.004A

v0=4.72V
 
orangeincup said:
Oh I see. I updated my solution:

(v0-24)/100+v0/25+0.004A=0

It is much better, but 40 mA=0.04 A.

ehild
 
Okay, I fixed it. v0=4.00V. Thank you.
 
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