How Do You Calculate Work, Internal Energy, and Heat in Compressed Air?

  • Thread starter Thread starter febbie22
  • Start date Start date
  • Tags Tags
    Energy Flow
Click For Summary
SUMMARY

This discussion focuses on calculating work, internal energy, and heat in a compressed air scenario involving 1 kg of air at an initial pressure of 100 kPa and a final pressure of 150 kPa, following the law pv1.3 = constant. The work done on the gas is calculated to be 816.67 J using the formula W = ((P1 * V1) - (P2 * V2)) / -0.3. The change in internal energy requires determining heat (Q) first, as indicated by the equation U2 - U1 = Q + W, where the internal energy of an ideal gas is expressed as U = Cv * n * T.

PREREQUISITES
  • Understanding of the ideal gas law and its applications
  • Familiarity with thermodynamic principles, specifically work and internal energy
  • Knowledge of specific heat capacities, Cv and Cp
  • Ability to manipulate equations involving pressure, volume, and temperature
NEXT STEPS
  • Study the derivation and application of the ideal gas law
  • Learn about the first law of thermodynamics and its implications
  • Explore the relationship between heat transfer and internal energy changes
  • Investigate the specific heat capacities of various gases under different conditions
USEFUL FOR

Students in thermodynamics, engineers working with gas compression systems, and anyone involved in energy calculations related to gases will benefit from this discussion.

febbie22
Messages
36
Reaction score
0

Homework Statement


1 kg of air at a pressure of 100 kPa occupying a volume of 0.025 m3 is
compressed to a pressure of 150 kPa according to the law
pv1.3 = constant.

Determine:
(i) Work done on or by the gas; (6)
(ii) Change in internal energy of the gas; (6)
(iii) Heat received or rejected by the gas; (4)

Take Cv = 0.718 kJ/kg K, Cp = 1.005 kJ/kg K


Homework Equations



In attachment the password is exam

The Attempt at a Solution



I think i can do the first part fine:

W= ((100*10^3) * 0.025 - (150*10^3) * 0.0183) / -0.3
= 816.67

Its the second part that i don't get as it asks for the change in internal energy before the heat received

is there a equation to calculate the internal energy as there is one here:

U2-U1= Q + W

but i would need to work out Q before U2-U1

any help would be much appreciated
 

Attachments

Physics news on Phys.org
The internal energy of an ideal gas is CvnT=CvPV/R.
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 12 ·
Replies
12
Views
4K
  • · Replies 10 ·
Replies
10
Views
2K
Replies
23
Views
5K
  • · Replies 11 ·
Replies
11
Views
8K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 10 ·
Replies
10
Views
2K
Replies
1
Views
2K
Replies
1
Views
2K