Non-inertial frame of reference

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SUMMARY

The discussion centers on calculating the acceleration of a speedboat using a non-inertial frame of reference. The problem involves a cork ball with a mass of 22.0g suspended at an angle of 32.5 degrees from the vertical. The correct acceleration of the speedboat is determined to be 6.2 m/s² when using the inertial frame, but the challenge lies in applying the concept of fictitious forces in a non-inertial frame. The fictitious force is defined as the product of mass and acceleration (ma), which is crucial for solving the problem correctly.

PREREQUISITES
  • Understanding of non-inertial frames of reference
  • Knowledge of fictitious forces in physics
  • Ability to perform vector resolution of forces
  • Familiarity with basic mechanics equations
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  • Study the concept of fictitious forces in non-inertial frames
  • Learn how to resolve forces in inclined planes
  • Explore the relationship between mass, acceleration, and force
  • Practice problems involving non-inertial reference frames
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Students studying physics, particularly those focusing on mechanics and reference frames, as well as educators seeking to clarify concepts related to non-inertial frames and fictitious forces.

rrosa522
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Homework Statement


You use a string to suspend a cork ball with a mass of 22.0g from the ceiling of a moving speedboat. The ball and string hang at 32.5 degrees from the vertical. Calculate the acceleration of the speedboat.

Homework Equations

The Attempt at a Solution


I was able to calculate using inertial frame of reference and I got 6.2m/s^2, which is the correct answer. But my teacher wants me to use non-inertial frame of reference to answers this question and I have no idea how.
My teacher said that the acceleration of the speedboat is equal to the fictitious force, but I found the fictitious force and it did not equal to 6.2
 
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rrosa522 said:
My teacher said that the acceleration of the speedboat is equal to the fictitious force, but I found the fictitious force and it did not equal to 6.2
The fictitious force equals ma, not a. (An acceleration would not even have the correct units.)
 

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