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Non Polynomial Hamiltonian Constraint

  1. Apr 25, 2014 #1
    1. Is the root(det(q)) term in the Hamiltonian Constraint what makes it non polynomial
    2. Is the motivation for Ashtekar Variables to remove the non polynomial terms by replacing the Hamiltonian with a densitised Hamiltonian
  2. jcsd
  3. Apr 26, 2014 #2


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    Science Advisor
    Gold Member

    I suggest you try the "Beyond the standard model" forum for questions regarding loop quantum gravity.
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