Nonlinear Equation: Solve x,y,z

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Homework Help Overview

The problem involves solving a set of nonlinear equations for the variables x, y, and z, given the relationships between them and constants a, b, and c, which are not equal to zero.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • The original poster expresses uncertainty about how to begin solving the equations and mentions finding a trivial solution. Other participants inquire about the specific attempts made and suggest rewriting the equations to explore potential substitutions.

Discussion Status

The discussion is ongoing, with participants exploring different approaches to the problem. Some guidance has been offered regarding rewriting the equations and substituting variables, but no consensus has been reached on a specific method or solution.

Contextual Notes

Participants note the challenge of starting the problem and the presence of a trivial solution, indicating that further exploration of non-trivial solutions is necessary.

dirk_mec1
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Homework Statement


Solve x,y and z from [tex] \frac{y+z}{a}= \frac{x+z}{b}=\frac{x+y}{c} = xyz[/tex]

wit a,b,c not equal to zero.

Homework Equations


The Attempt at a Solution


I have no idea how to start. I've tried several things but it seems like I'm missing something. I did find the trivial solution (0,0,0).
 
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dirk_mec1 said:

Homework Statement


Solve x,y and z from [tex] \frac{y+z}{a}= \frac{x+z}{b}=\frac{x+y}{c} = xyz[/tex]

wit a,b,c not equal to zero.

Homework Equations





The Attempt at a Solution


I have no idea how to start. I've tried several things but it seems like I'm missing something. I did find the trivial solution (0,0,0).

You say you tried several things. What were they? You need to show your work.
 
dirk_mec1 said:

Homework Statement


Solve x,y and z from [tex] \frac{y+z}{a}= \frac{x+z}{b}=\frac{x+y}{c} = xyz[/tex]

wit a,b,c not equal to zero.

Homework Equations


The Attempt at a Solution


I have no idea how to start. I've tried several things but it seems like I'm missing something. I did find the trivial solution (0,0,0).

Rewrite the equation as
$$\frac{1}{a}\left(\frac{1}{xz}+\frac{1}{xy}\right)=\frac{1}{b} \left( \frac{1}{yz}+\frac{1}{xy}\right)=\frac{1}{c}\left(\frac{1}{yz}+\frac{1}{xz}\right)=1$$
Substitute ##1/(xy)=p, 1/(yz)=q## and ##1/(xz)=r##. Form three equations to find p, q and r. This gives the possible non-zero solutions.
 
Understood, thanks.
 

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