Normal distribution curve area?

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A simple algorithm for computing the area under the normal distribution curve for specific sigma values, such as 2.5 sigma, does not exist in elementary functions. The standard normal distribution probability requires numerical integration or reference to pre-calculated tables. Programs like Wolfram Alpha, MMA, and Matlab can perform these definite integrals effectively. The known percentages for 1, 2, and 3 sigma are 68.3%, 95%, and 99.7%, respectively. For values outside these, numerical methods or tables are necessary for accurate results.
Scott S
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Is there a relatively simple algorithm to compute the area in percentage under the curve as represented by a sigma value?
For example;
3 sigma = 99.7
2 sigma = 95
1 sigma = 68.3
Now suppose I wanted to know 2.5 sigma without a table.
 
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Wolfram Alpha, MMA, Matlab, and other programs are pretty good at definite integrals.
 
No, there isn't. The standard normal distribution probability that "z< a" is \frac{1}{\sqrt{2\pi}}\int_{-\inf}^a e^{-\frac{x^2}{2}} dx. That cannot be integrated in terms of elementary functions so either do a numerical integration or use a table (which was developed by numerical integrations).
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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