Is the Normal Force in an Elevator Conservative?

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SUMMARY

The discussion centers on whether the normal force in an elevator is a conservative force. It is established that the normal force is not conservative because, during the elevator's descent, the work done on a body is positive when it passes the second floor, indicating that the total work is not zero in a closed path. The normal force acts upward even when the elevator accelerates downward, contradicting the criteria for conservative forces. Therefore, the normal force cannot be classified as conservative.

PREREQUISITES
  • Understanding of conservative forces in physics
  • Knowledge of work-energy principles
  • Familiarity with Newton's laws of motion
  • Basic concepts of kinetic energy
NEXT STEPS
  • Study the characteristics of conservative and non-conservative forces
  • Explore the work-energy theorem in detail
  • Investigate the implications of normal force in various acceleration scenarios
  • Learn about the dynamics of elevators and their effect on occupants
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Physics students, educators, and anyone interested in understanding the dynamics of forces in non-inertial reference frames, particularly in the context of elevators.

Caio Graco
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Homework Statement
Can normal force work? If so, is it a conservative force?
Relevant Equations
There is no equation for normal force.
Consider a body inside an elevator. When it goes up and down, I believe that normal work (positive on the rise and negative on the descent). My question is: since the total work on the closed path is zero, can we say that the normal force is conservative?
 
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Caio Graco said:
Consider a body inside an elevator. When it goes up and down, I believe that normal work (positive on the rise and negative on the descent).
Simply not true. When accelerating down the elevator exerts a normal force that is still "up" (not negative) and large enough so that your acceleration matches the elevator's acceleration. If that were not the case, you would either hit the roof or, even worse, fall through the floor.

You need to think what the criterion for a conservative force is.
 
Caio Graco said:
Consider a body inside an elevator. When it goes up and down, I believe that normal work (positive on the rise and negative on the descent). My question is: since the total work on the closed path is zero, can we say that the normal force is conservative?
Suppose that you step into the elevator on the 2nd floor. The elevator is at rest. Your kinetic energy is zero.

You press the button labelled "3" and rise to the third floor. The elevator stops here. You press the button labelled "1" (or "G"). The elevator proceeds downward past the 2nd floor without stopping.

At the moment that the elevator passes the second floor is your kinetic energy greater than, less than or equal to what it was when you first pressed the "3" button? At this moment, is is the total work that has been done on you by the elevator positive, negative or zero?
 
jbriggs444 said:
Suppose that you step into the elevator on the 2nd floor. The elevator is at rest. Your kinetic energy is zero.

You press the button labelled "3" and rise to the third floor. The elevator stops here. You press the button labelled "1" (or "G"). The elevator proceeds downward past the 2nd floor without stopping.

At the moment that the elevator passes the second floor is your kinetic energy greater than, less than or equal to what it was when you first pressed the "3" button? At this moment, is is the total work that has been done on you by the elevator positive, negative or zero?

By the time the elevator passes the second floor, my kinetic energy is greater than it was at the beginning. So the total work on me is positive. And I believe this shows that the normal force is not conservative because there is at least one case, like this, in which in a closed trajectory the total work is not zero. Is this friend?
 
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Caio Graco said:
the normal force is not conservative because there is at least one case, like this, in which in a closed trajectory the total work is not zero
Yes.
 
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