Normal forces for small car performing a vertical loop

[Anatalbo]

Homework Statement

A small car with mass .800 kg travels at a constant speed of 12m/s on the inside of a track that is a vertical circle with radius 5.0m. If the normal force exerted by the track on the car when it is at the top of the track is 6.00N, what is the normal force at the bottom of the track?

Reference https://www.physicsforums.com/threa...mics-car-traveling-in-vertical-circle.656316/

Homework Equations

The Attempt at a Solution

I got that the acceleration towards the center of the circle is 17.31 m/s^2

 

[Greg Bernhardt]

Please show your work.

 

[Anatalbo]

Please show your work.

N+w=FC (normal force, weight, centripetal force)

6N+(9.81)(0.8)=0.8a
a=17.31 m/s^2

 

[PhanthomJay]

N+w=FC (normal force, weight, centripetal force)

6N+(9.81)(0.8)=0.8a
a=17.31 m/s^2

Ignore the given constant speed of 12m/s, as it is incorrectly stated as such, which you will discover by reading the thread you referenced. So you now have the correct centripetal acceleration. So now show how you would calculate the normal force at the bottom, assuming the car's speed is constant.

 

[Anatalbo]

Ignore the given constant speed of 12m/s, as it is incorrectly stated as such, which you will discover by reading the thread you referenced. So you now have the correct centripetal acceleration. So now show how you would calculate the normal force at the bottom, assuming the car's speed is constant.

Thanks! I was confused about why the values didn't add up