- #1

Nikitta

- 5

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- Homework Statement
- In a vertical circle more specifically in a pendulum ride, there is a tension force acting on the gondola and a reaction force by the gondola acting on the passengers. How do you know the tension force and reaction force are equal and how do you find the reaction/tension force at the bottom of the circle?

- Relevant Equations
- T = mv^2/r + mg

Ep=mgh

V (critical) = SQRT(gr) (velocity at top of circle)

Ek (lin) = 1/2mv^2

Ek (rot) = 1/2Iw^2

Ek (total) = 1/2mv^2 + 1/2Iw^2

At the bottom of the circle, the tension force is greater than the weight force as there must be a net force acting towards the centre to provide the centripetal force causing the centripetal acceleration and thus the circular motion. In the equation above (T = mv^2/r + mg) I only have the mass and radius. I tried to find the velocity of the object at the bottom of the circle by using conservation of energy (Ep lost = Ek gained). I tried to find the total energy of the system, gravitational potential, linear and rotational kinetic energy at the top, however, I could not find the rotational kinetic energy (don't have I). Does the rotational kinetic energy need to be taken into account (In other problems about vertical circle the rotational kinetic is usually not involved, is there any rotational kinetic energy?)

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