Normal forces on stud at points A and B with applied moment

[yoda2026]

Homework Statement

ive been trying to figure our this mechanics question and I am rather stuck
but unfortunately i haven't had much experience with moments

find the normal forces applied to the installed stud at points A and B
[PLAIN]http://img851.imageshack.us/img851/1826/photoc.jpg


length from P to A = 360MM
length of A to B = 85mm
thickness of timber between A and B is 45mm (or vertical distance between A and B)

for applied at point P is 150N

ignore friction

formulas
M= f(a+d)=fa
m=fd

so far i understand that the force applied to the centre of the stud
is 360/1000 * 150N = 54NM

then you have a couple of 85/1000 * 150N = 12.75nm

is this the correct way of attempting this question
if so how does the couple and the for applied to the lever interact to give me the force on points A and B of the stud?

 

[PhanthomJay]

The way to solve this problem is to use the equilibrium equations:
sum of forces in horizontal direction =0,
sum of forces in vertical direction = 0,
and sum of moments about any point =0.

Try summing moments about B or A.