Physics Problem: Determining Applied and Normal Forces on a Vertical Window

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SUMMARY

The discussion focuses on calculating the applied and normal forces on a sponge being pushed up a vertical window. The sponge has a mass of 0.800 kg and a coefficient of kinetic friction of 0.253. The user correctly identifies that the applied force can be determined using the equations of motion and friction. The calculations involve using trigonometric functions and the Pythagorean theorem to find the magnitude of the applied force and the normal force exerted by the window.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Knowledge of frictional forces and coefficients
  • Familiarity with trigonometric functions in physics
  • Ability to apply the Pythagorean theorem in force calculations
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  • Study the application of Newton's second law in vertical motion
  • Learn about the effects of friction in inclined planes
  • Explore the relationship between normal force and applied force in different scenarios
  • Practice solving problems involving forces at angles using trigonometric identities
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Students studying physics, particularly those focusing on mechanics and force analysis, as well as educators seeking to clarify concepts related to applied and normal forces.

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Physics prob 2 ... Help needed!

Homework Statement



Like i sayed in my other posts this is probably easy but my teacher doesn't teach us anything so i don't have a clue how to do this. Can someone please explain how to do it?

A window washer pushes a sponge up a vertical window at a constant speed by applying a force. The sponge has a mass of .800 kg, and the coefficient of kinetic friction between the sponge and window is u_k=0.253. Determine the magnitude of the applied force, and the magnitude of the normal force exerted by the window on the sponge.

*There is a 20 degree angle( i put the pic below)

Homework Equations



F(y) = weight of sponge + Frictional force

F(f) = u*F(x)

The Attempt at a Solution



ok so what i did was that i took the sin 70 which if I'm not mistaken should equal F(x).
sin 70=F(x)
.94=F(x)

Then I put this in the equation for frictional force.
F(f)=uF(x)
F(f)=(.253)(.94)
F(f)=.238

After that I put it into the equation for F(y).
F(y)=weight of sponge + F(f)
F(y)=(.8)+(.238)
F(y)=1.048

My plan is to do the pythagorian therum to find the applied force, but I want to make sure i am doing it right so far.
 

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F(x) = F * sin(70)

where F is magnitude of the applied force.
 

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