Normal Modes and Frequencies of Coupled Oscillators?

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SUMMARY

The discussion focuses on the normal modes and frequencies of two coupled undamped oscillators, where the coupling force is defined by the constant \(\alpha\) and the equations of motion for each oscillator. The correct equations of motion are established as \(m\frac{d^2x_a}{dt^2} = \alpha\frac{d^2x_a}{dt^2} - k(x_a)\) and \(m\frac{d^2x_b}{dt^2} = \alpha\frac{d^2x_b}{dt^2} - k(x_b)\), incorporating the restoring force \(k\). The challenge lies in properly integrating the coupling constant into the analysis of the system's dynamics and determining the normal modes and their corresponding frequencies.

PREREQUISITES
  • Understanding of coupled oscillators and their dynamics
  • Familiarity with Newton's second law of motion
  • Knowledge of normal mode analysis in mechanical systems
  • Basic grasp of differential equations
NEXT STEPS
  • Study the derivation of normal modes for coupled oscillators
  • Learn about the role of coupling constants in oscillatory systems
  • Explore the mathematical techniques for solving second-order differential equations
  • Investigate the effects of damping and restoring forces on coupled oscillators
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Students and educators in physics, particularly those focusing on mechanics and oscillatory motion, as well as researchers interested in the dynamics of coupled systems.

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Homework Statement



Two identical undamped oscillators are coupled in such a way that the coupling force exerted on oscillator A is \alpha\frac{d^2x_a}{dt^2} and the coupling force exerted on oscillator B is \alpha\frac{d^2x_b}{dt^2} where \alpha is a coupling constant with magnitude less than 1. Describe the normal modes of the coupled system and find their frequencies.

The Attempt at a Solution



I know this isn't much of an attempt, but I've searched online and in the text... what am I supposed to do with this coupling constant?
 
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Start by writing the equation of motion for both oscillators.
 
That's where I'm stuck...

m\frac{d^2x_a}{dt^2}=\alpha\frac{d^2x_a}{dt^2}
m\frac{d^2x_b}{dt^2}=\alpha\frac{d^2x_b}{dt^2}

?
 
I'd be glad to show more work if I knew what to do with this coupling constant!
 
mathman44 said:
That's where I'm stuck...

m\frac{d^2x_a}{dt^2}=\alpha\frac{d^2x_a}{dt^2}
m\frac{d^2x_b}{dt^2}=\alpha\frac{d^2x_b}{dt^2}

?
Those equations say the only force on the masses is the coupling force. What about the restoring force?
 
m\frac{d^2x_a}{dt^2}=\alpha\frac{d^2x_a}{dt^2} - k(x_a)
m\frac{d^2x_b}{dt^2}=\alpha\frac{d^2x_b}{dt^2} - k(x_b)
 

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