Normal Stress in Rods Experiencing Temperature Changes

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Qube
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Homework Statement
The rods are experience different temperature changes. Find the normal stress in rod AB.
Relevant Equations
Change in length of a rod due to temperature = alpha*temperature change*original length

Change in length of a rod due to a normal force: FL/AE
Diagram of two rods joined at collar B and fixed between walls at A and C. Rod AB is labeled Material-1 (3E, 2α), length 3L, diameter D = 2r. Rod BC is labeled Material-2 (2E, 3α), length 2L, diameter D = 2r.


Now here is the part where I'm sort of stumped myself:

Handwritten-style typed worked solution on a bar-compatibility problem: equilibrium F_A = F_C = F, compatibility delta_ac = 0, sum of deltas equals zero, then simplified equations involving 6 alpha Delta T L and FL/AE terms, ending with delta_ab,T = delta_bc,T = 6 alpha Delta T L.


Could someone let me know if my reasoning is valid? The professor explained it during office hours and all I got out of that was that something cancels out and the answer is 0.
 
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I'm having trouble understanding what you did. Let ##\delta## represent the displacement of point B to the right. Then the change in length of rod AB is ##+\delta## and the change in length of rod BC is ##-\delta##. So the total strain in rod AB is ##\epsilon=+\frac{\delta}{3L}## and the total strain in rod BC is ##\epsilon=-\frac{\delta}{2L}##. For a rod that experiences both thermal expansion and tensile stress ##\sigma##, the relationship between tensile stress, total strain, and temperature change is $$\sigma=E(\epsilon-\alpha \Delta T)$$
 
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