- #1

jessedupont

- 3

- 0

the first is psi=(2-(r/asub0))*e^(-r/asub0)

the second is psi=rsin(theta)*cos(phi)*e^(-r/2asub0)

I know these need to be in the form (where psi will be name y for simplicity sake)

1=int(Y*Ydtao). and this will eventually come to the form (let ~ be the symbol for integral where 1~2 is the integral from 1 to 2 for example.)

1=0~2pi 0~pi 0~inf r^2dr*sin(theta)*dtheta*dphi

then i need to confirm that these two functions are mutually orthogonal but as long as I can integrate them I should be able to figure out all that.

Thanks!!