Normalization and singularities

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SUMMARY

This discussion addresses the relationship between normalization and singularities in probability distributions. It concludes that normalization does not eliminate singularities, as demonstrated through the example of a classical harmonic oscillator. The probability density function P(x) becomes infinite at the endpoints x = ±a, yet remains integrable over the interval [-a, a], confirming that singularities can exist without violating normalization. The conversation emphasizes the need for careful interpretation of singularities in mathematical contexts.

PREREQUISITES
  • Understanding of probability density functions
  • Familiarity with normalization techniques in mathematics
  • Knowledge of classical mechanics, specifically harmonic oscillators
  • Basic calculus, particularly integration of functions
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  • Study the properties of probability density functions and their normalization
  • Explore the concept of integrable functions in mathematical analysis
  • Learn about singularities in mathematical physics and their implications
  • Investigate the behavior of classical harmonic oscillators and their probability distributions
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Mathematicians, physicists, and students studying probability theory and classical mechanics who seek to understand the implications of normalization and singularities in mathematical functions.

diegzumillo
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Hi There!

Being direct to the point: Does normalization removes singularities? Such as infinite.

I came up with this question because, while I was working with a not normalized function, I reached a very strange result. There are two points where the probability tends to infininte.

Maybe that's because the function is not normalized. (intuitively, I thought the normalization would only re-scale the 'curve', when plotted) Or did I mess up the calculation?

If anyone wants to see more than that first question, I can show the equations I'm working. So we can have a more specific discussion. :)
 
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Diego Floor said:
Hi There! Being direct to the point: Does normalization removes singularities?
No.
Diego Floor said:
I came up with this question because, while I was working with a not normalized function, I reached a very strange result. There are two points where the probability tends to infininte.
That's possible if the probability distriubtion is integrable at these points. For example, consider a classical harmonic oscillator with x=a\cos(\omega t). If you look at it at a random time, the probability that you will find it between x and x+dx is P(x)dx, with

P(x)={1\over\pi}\,{1\over\sqrt{a^2-x^2}

for -a\le x\le a, and P(x)=0 otherwise. P(x) becomes infinite at x=\pm a, but still \int_{-a}^{+a}P(x)dx = 1.
 
Thanks! :D

I didn't remember that example, it really clarifies things out.

Ok, singularities are not evil! They just have a 'not so trivial' interpretation.
 

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