Normalization constant A of a harmonic oscillator

Click For Summary
SUMMARY

The discussion focuses on the normalization constant A of a harmonic oscillator's wavefunction. The user attempted to normalize the wavefunction, resulting in an undefined expression of 1/0, indicating a miscalculation. Key points include the importance of using absolute values correctly in complex numbers and the proper application of orthonormality principles. The correct approach involves calculating the modulus of a complex number using the formula sqrt(a^2 + b^2) and ensuring that the wavefunction is properly normalized to unity.

PREREQUISITES
  • Understanding of quantum mechanics wavefunctions
  • Familiarity with complex numbers and their properties
  • Knowledge of normalization and orthonormality in quantum mechanics
  • Ability to perform algebraic manipulations with complex expressions
NEXT STEPS
  • Study the normalization of quantum mechanical wavefunctions
  • Learn about the properties of complex numbers, specifically modulus and absolute values
  • Explore the concept of orthonormality in quantum states
  • Review algebraic techniques for manipulating complex expressions in quantum mechanics
USEFUL FOR

Students and professionals in quantum mechanics, physicists working with harmonic oscillators, and anyone interested in the mathematical foundations of wavefunctions.

Sorin2225
Messages
20
Reaction score
1
Homework Statement
Finding the normalization constant A of a harmonic oscillator
Relevant Equations
(psi(x,t))^2=1
media_df0_df08153c-e951-4140-bf30-75ec0c2140b9_phpO7r43W.png
IMG_20200427_121732.jpg


I've worked through it doing what I thought I should have done. I normalized the original wavefunction(x,0) and made it = one before using orthonormality to get to A^2(1-1) because i^2=-1 but my final answer comes out at 1/0 which is undefined and I don't see how that could be correct since A is meant to be a real number. I'm not really sure where I've gone wrong either so any insight would be appreciated.
 
Physics news on Phys.org
##\lvert \psi_1 + i \psi_4 \rvert^2 \ne (\psi_1 + i \psi_4)^2##

The vertical lines matter.
 
So it's the absolute value? which means that it's +1 not -1?
 
What is “it”?
 
|iψ4*iψ4|
 
That's not how absolute values work. You can't say ##\lvert a+b \rvert = \lvert a \rvert + \lvert b \rvert## in general.

How do you calculate the modulus of a complex number?
 
sqrt(a^2+b^2) so it would be Sqrt((i^2)^2+((psi(4)^2)^2))
 
##|\Psi|^2=\Psi^*\Psi=[A(\psi_1+i\psi_4)][A^*(\psi^*_1-i\psi^*_4)]##. What do you get when you multiply it out?
 

Similar threads

  • · Replies 16 ·
Replies
16
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
11
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
4
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K