Normalizing a wavefunction f(x) = e^-|2x|

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SUMMARY

The wavefunction f(x) = e^-|2x| requires normalization to satisfy the condition S f^2 dx = 1, where S denotes the integral from -∞ to +∞. The normalization process involves calculating the integral S [(Ae^-|2x|)^2] dx, leading to A^2 S (e^-4|x|) dx = 1. The correct normalization constant A is determined to be 2 after addressing the factor of 2 that arises when splitting the integral from -∞ to 0 and 0 to +∞. This ensures the wavefunction is properly normalized for quantum mechanical applications.

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Homework Statement


This isI n't formatted properly because I don't have much time.

The wave function is f(x) = e^-|2x|

I need to normalize this function

Homework Equations



The normalization condition is

S f^2dx=1

(that S is an "integral" sign and the limits are from - infinity to + infinity)

The Attempt at a Solution



S [(Ae^-|2x|)^2]dx = 1

A^2 S (e^-2|2x|)dx = 1

A^2 S (e^-4x)dx = 1

(-1/4)(A^2)(e^-4(infinity) - e^-4(0)) = 1
(-1/4)(A^2)(-1) = 1
A = sqrt(4)
A = 2

this doesn't seem right? can someone help? I'm pressed for time.
 
Last edited:
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You missed a factor of 2 when you went from an integral from -infty to +infty, to an integral from -infty to 0.
 

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