Not enough information for question? [1st year special relativity]

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Homework Help Overview

The discussion revolves around a special relativity problem involving a meson with a given mean lifetime in its rest frame and its decay into a muon and a neutrino. The question seeks to determine the speed required for the meson to travel a specified distance in the lab frame.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the relationship between reference frames and the application of relativistic concepts such as time dilation and length contraction. There is uncertainty about how to start the problem and whether standard equations like v=s/t can be applied in relativistic contexts.

Discussion Status

Some participants have provided hints about using the relationship between speed and distance in different frames, while others have clarified that the equation v=s/t is valid in any frame as long as consistent measurements are used. The discussion is ongoing, with various interpretations being explored.

Contextual Notes

There is a noted confusion regarding the application of relativistic effects and the need to ensure that time and distance measurements are taken from the same reference frame. Participants are questioning the adequacy of the information provided in the problem statement.

radiator0505
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Homework Statement



I've been going over past papers recently and I can't see how to start this one, I get confused with the reference frames and it looks like I don't have enough information to start this.

"An unspecified meson has a mean lifetime , defined in its rest frame, of t = 2.60x10^-8. The meson decays into a muon and a neutrino. At what speed does the meson have to be moving for it to travel a distance of 20m in the lab frame?"

Homework Equations



T=γt
L=l/λ
v=s/t (not sure about this one, would i need to use the relativistic velocity?)

The Attempt at a Solution


I can't see how to start, if I could figure out gamma or either of τ and l I think I can do it.
 
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Hint: γ is a function of v, so an equation with γ can be written in terms of v.

Pick either frame to work with. One frame you'll need length contraction; the other frame you'll need time dilation. Take your pick!
 
But how do I find (for example) t?
I can;t just use v=s/t can I?
 
radiator0505 said:
But how do I find (for example) t?
The time is given (at least in the muon's frame). It must travel the given distance before it decays.
I can;t just use v=s/t can I?
Sure you can.
 
Doc Al said:
Sure you can.

Really? Does it not matter that the particles relativistic?
Is the only frame where stuff like v=s/t doesn't hold a relativistic one?
 
I think what DocAl is getting at is in the observers reference frame you can use v=s/t as your just trying to find out how long it takes for the meson to travel that distance. This is how long it will take as seen by the observer, however the clock on the meson is ticking much slower and relativity should be used when working in the mesons reference frame
 
radiator0505 said:
Really? Does it not matter that the particles relativistic?
Is the only frame where stuff like v=s/t doesn't hold a relativistic one?
v = s/t works in any frame and for any speed. It's the definition of speed.

Just be sure that you use the distance and time measurements from the same frame. Don't mix distance from one frame with time from another.

Relativity comes into the picture when you want to transform distance or time measured in one frame to that measured in another. And that's exactly what you need to do here, since the time and distance that you are given are from different frames. Pick one and go for it.
 
well i was wrong. thanks DocAl. Do you know anything about QM? do u think you could help me out wit my most recent post ?
 
Doc Al said:
v = s/t works in any frame and for any speed. It's the definition of speed.

Just be sure that you use the distance and time measurements from the same frame. Don't mix distance from one frame with time from another.

Relativity comes into the picture when you want to transform distance or time measured in one frame to that measured in another. And that's exactly what you need to do here, since the time and distance that you are given are from different frames. Pick one and go for it.

Brilliant, completely cleared that up.
Thanks!
 

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