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Homework Statement
Look below for diagram
Mass m_{1}is on an inclined plane and weighs 1.00 kg. The inclined plane creates a 40.0 degree angle with the ground, and μ_{k} = 0.225. Mass m1_{1} is attached to a weight hanging off the edge via pulley, called M_{2}. M_{2} has a mass of 1.50kg and hangs from a height h of 50.0 cm. When the system is released from rest, how long will it take M_{2} to hit the floor? Assume the static frction is exceeded by the weight of M_{2}
Homework Equations
d=1/2(a)(t^{2})
f=ma (or f = mg)
f1 = MgSin∅
f2 = mg
a = net force/net weight
a = (m_{2}gm_{1}gsin∅)/(m_{1}+m_{2})  not sure how this was derived, was in my book
The Attempt at a Solution
a=(1.5 kg ) (9.8 m/s^{2})(1 kg ) (9.8 m/s2) sin(40)
(1 kg )+(1.5 kg )
This solution feels wrong and I'm very sure I did it wrong. Please look it over for me; I'm terribly confused by this problem.
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