(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

Figure 5-60 shows a box of dirty money (mass m1 = 2.7 kg) on a frictionless plane inclined at angle θ1 = 28°. The box is connected via a cord of negligible mass to a box of laundered money (mass m2 = 2.4 kg) on a frictionless plane inclined at angle θ2 = 64°. The pulley is frictionless and has negligible mass. What is the tension in the cord?

2. Relevant equations

F = ma

T - mgsin[tex]\Theta[/tex] = -ma

a = ( m / M + m )g

3. The attempt at a solution

Newton's 2nd law for each body:

m1: T - (2.7 kg)(9.8 m/s2)sin28 = -(2.7 kg)a

m2: (2.4 kg)(9.8 m/s2)sin68 - T = -(2.4 kg)a

Add m1 & m2: (2.4 kg)(9.8 m/s2)sin68 - (2.7 kg)(9.8 m/s2)sin28 = (2.4 + 2.7)a

Solve for a: a = 1.84

Insert a into m1: T-(2.7 kg)(9.8 m/s2)sin28 = -(2.7 kg)(1.84 m/s2)

T = 17.4 N

However, that is not the right answer... Where am I going wrong?

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# Tension of 2 Bodies on a Frictionless Inclined Plane

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