Novas and special relativity-check my work?

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Homework Help Overview

The problem involves the observation of two novas occurring simultaneously from the perspective of Earth astronomers, with a focus on how time is perceived by observers on an aircraft moving between the two novas. The subject area relates to special relativity and time dilation effects.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to apply the Lorentz transformation to determine the time interval between the novas as perceived by observers on the aircraft. Some participants question the accuracy of the beta value used in the calculations, while others seek clarification on the conversion from years to hours.

Discussion Status

The discussion is active, with participants providing feedback on the calculations and seeking clarification on specific steps. There is no explicit consensus, but some guidance has been offered regarding the accuracy of the beta value and the conversion process.

Contextual Notes

Participants are exploring the implications of special relativity in the context of simultaneous events and the effects of relative motion on time perception. There may be assumptions about the accuracy of the Lorentz transformation application and the definitions of the variables involved.

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Novas and special relativity--check my work?

Homework Statement


Suppose Earth astronomers see two novas occur simultaneously, one in constellation Orion and the other in Lyra. Both nova are the same distance from Earth (2.5e3 cy) and are in exactly opposite directions from Earth. Observers are on board an aircraft flying at 1000 km/h on a line from Orion toward Lyra.

a) for the observers on the aircraft, how much time separates the nova?


Homework Equations


v=1000 km/hr = 277.78 m/s =9.26e7*c
Beta = 9.26e7
Gamma= approximately 1

The Attempt at a Solution



a) I will say that the astronomers see the novas both occur at t1(Orion)=t2(Lyra)=0 and that the origin of the Earth's frame is on the Earth.
Applying the Lorentz transform:
t1'=1*(0-(9.26e7*c)(-2.5e3cy)/c^2) = 0.002315 y
t2'=1*(0-(9.26e7*c)(2.5e3cy)/c^2) = -0.002315 y

Therefore, the interval measured by the observers on the aircraft is 0.00463 y = 40.56 hr.
The observers on the aircraft see the nova on Lyra occur first.

Is this correct?
 
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bcjochim07 said:
Beta = 9.26e7

You mean 9.26e(-7) right?...Other than that, everything looks correct!:approve:
 


Hi I was wondering how you went from 0.00463y to 40.56 hr
Thanks
 


Uhh, conversion? .00463 year * 365 day/year * 24 hour/day?
 


Of course :-p I was thinking to complicated about it lol Thx
 

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