Novas and special relativity-check my work?

  • Thread starter bcjochim07
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Novas and special relativity--check my work?

Homework Statement


Suppose earth astronomers see two novas occur simultaneously, one in constellation Orion and the other in Lyra. Both nova are the same distance from Earth (2.5e3 cy) and are in exactly opposite directions from Earth. Observers are on board an aircraft flying at 1000 km/h on a line from Orion toward Lyra.

a) for the observers on the aircraft, how much time separates the nova?


Homework Equations


v=1000 km/hr = 277.78 m/s =9.26e7*c
Beta = 9.26e7
Gamma= approximately 1

The Attempt at a Solution



a) I will say that the astronomers see the novas both occur at t1(Orion)=t2(Lyra)=0 and that the origin of the Earth's frame is on the Earth.
Applying the Lorentz transform:
t1'=1*(0-(9.26e7*c)(-2.5e3cy)/c^2) = 0.002315 y
t2'=1*(0-(9.26e7*c)(2.5e3cy)/c^2) = -0.002315 y

Therefore, the interval measured by the observers on the aircraft is 0.00463 y = 40.56 hr.
The observers on the aircraft see the nova on Lyra occur first.

Is this correct?
 

Answers and Replies

  • #2
gabbagabbahey
Homework Helper
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Beta = 9.26e7

You mean 9.26e(-7) right?....Other than that, everything looks correct!:approve:
 
  • #3
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Hi I was wondering how you went from 0.00463y to 40.56 hr
Thanks
 
  • #4
Char. Limit
Gold Member
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Uhh, conversion? .00463 year * 365 day/year * 24 hour/day?
 
  • #5
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Of course :tongue2: I was thinking to complicated about it lol Thx
 

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