Nuclear diamters will a meson traverse?

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Discussion Overview

The discussion revolves around the traversal distance of a pi-zero meson through nuclear diameters before it decays, specifically at a speed of 0.95c. It touches on concepts of particle decay, relativistic parameters, and the application of Lorentz transformations in this context.

Discussion Character

  • Exploratory
  • Technical explanation
  • Mathematical reasoning

Main Points Raised

  • One participant inquires about the number of nuclear diameters a pi-zero meson will traverse before decaying, given its mass and lifetime.
  • Another participant provides a formula for the decay length in the lab frame, L = βγcτ, and explains the terms involved, including the Lorentz parameters β and γ.
  • A request for clarification on the definition of Lorentz parameters is made, leading to a detailed explanation of their roles in relativistic transformations.
  • Further elaboration on the derivation of the decay length formula is provided, linking it to the relativistic decay lifetime and velocity.
  • Participants express appreciation for the detailed mathematical discussion and the information shared.

Areas of Agreement / Disagreement

Participants generally agree on the use of the decay length formula and the definitions of Lorentz parameters, but the initial inquiry about the number of nuclear diameters traversed remains unresolved.

Contextual Notes

The discussion does not resolve the specific question regarding the number of nuclear diameters traversed, and assumptions regarding interactions with the nucleus are not explicitly addressed.

clockworks204
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nuclear diameters will a meson traverse?

Approximately how many nuclear diameters (A=100) will a (pi)0 meson traverse at a speed of 0.95c before it decays?

My textbook is very vague for the chapter containing this material. The only thing that is really given is that the mass is 135.0 MeV/c2 and its lifetime is 0.84x10-16s.
 
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If the pi-zero did not interact with the nucleus, then the decay length in the lab is

L = βγcτ

where β and γ are the relativistic Lorentz parameters, c is the speed of light, and τ is the undilated (center-of-mass) lifetime.

Bob S
 
Thank you for your reply. Can you please specify what exactly a lorentz parameter is?
 
clockworks204 said:
Thank you for your reply. Can you please specify what exactly a lorentz parameter is?
The velocity of the particle is v = βc, and γ= 1/sqrt(1-β2). Both β and γ are used in the Lorentz transformation from one moving relativistic reference frame to another. For the relativistic decay length L = βγcτ, the velocity is βc, and the time-dilated decay lifetime τ in the laboratory reference frame is γτ, so the decay length in the laboratory reference frame is velocity times time, or L = (βc)(γτ) = βγcτ. A complete (perhaps too mathematical) discussion of Lorentz transformations between different relativistic inertial reference frames is given in

http://hyperphysics.phy-astr.gsu.edu/hbase/relativ/ltrans.html

http://en.wikipedia.org/wiki/Lorentz_transformation

See also Section 38.1 in kinematics section in http://pdg.lbl.gov/2009/reviews/contents_sports.html

Bob S
 
Thanks Bobs for the great discussion, and the formula it very detailed. Well done.
 
I do appreciate the info
 

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