How Old is the Rock with a 3:1 Ratio of 207Pb to 235U?

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SUMMARY

The age of a rock with a 3:1 ratio of 207Pb to 235U can be determined using the decay constant derived from the half-life of 235U, which is 0.71 billion years. The decay constant is calculated as 9.76 x 10-10. Given that 3 out of every 4 U-235 nuclei have decayed to Pb-207, the remaining nuclei (N0) can be established as 1/4 of the original amount. This leads to the conclusion that the age of the rock is approximately 2.13 billion years.

PREREQUISITES
  • Understanding of radioactive decay and half-life concepts
  • Familiarity with the decay constant calculation
  • Knowledge of the relationship between parent and daughter isotopes in radiometric dating
  • Basic proficiency in natural logarithms and exponential functions
NEXT STEPS
  • Study the principles of radiometric dating using isotopes like U-235 and Pb-207
  • Learn about the calculation of decay constants and their applications in geology
  • Explore the concept of initial conditions in decay problems
  • Investigate other isotopic dating methods and their half-lives
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Geologists, students studying Earth sciences, and anyone interested in understanding radiometric dating techniques and the age determination of geological samples.

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Homework Statement



A rock contains three 207Pb nuclei for every 235U nucleus. Determine the age of the rock assuming all of the 207Pb was formed through the decay of uranium. (The half life of 235U is 0.71x109).

Homework Equations



N=N0e-λt

The Attempt at a Solution



So the decay constant is ln 2/T1/2=9.76x10-10. So

N0 = 1 e(9.76x10-10)t

But the problem is I don't know how to find N0, the remaining nuclei. How could I find it using the information given? They just say there are 3 Pb's for every uranium nucleus... How do we find the amount decayed so we can subtract it from the total to get the remaining N0? :confused:
 
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Look at the problem this way: When the rock was formed, there was no Pb-207 present because the U-235 had not begun to decay. In the present, assume that each Pb-207 nucleus resulted from the decay of a U-235 nucleus present at the time of formation. The initial concentration of lead was 0% of the number of U-235 nuclei. By the present time, 3 out of every 4 U-235 nuclei have decayed to Pb-207.

Instead of trying to find how many nuclei existed, find out how long it took for the present ratio of lead to uranium nuclei to be created.
 
SteamKing said:
Look at the problem this way: When the rock was formed, there was no Pb-207 present because the U-235 had not begun to decay. In the present, assume that each Pb-207 nucleus resulted from the decay of a U-235 nucleus present at the time of formation. The initial concentration of lead was 0% of the number of U-235 nuclei. By the present time, 3 out of every 4 U-235 nuclei have decayed to Pb-207.

Instead of trying to find how many nuclei existed, find out how long it took for the present ratio of lead to uranium nuclei to be created.

Thank you 3/4 have decayed so 1/4 left, so that gave me the correct answer. Thanks! :smile:
 

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