- #1
jacoja06
- 4
- 0
Hi everyone.
This question is giving me a real headache (literally). It should be simple, but I’ve spend probably the last 4-5 hours trying to figure it out. The left side of my brain is redundant.
The following specifications are used for the design of a flanged coupling between two coaxial shafts:
Speed: 650rpm
Power transmitted: 550 kW
Bolt diameter: 12mm
Pitch-circle diameter: 200mm
Material: Mild steel
Factor of safety: 4
Determine the number of bolts required, assuming the bolts are equally loaded.
Ultimate Shear Strength of mild steel = 360 N/mm^2
Shear stress (MPa) = Force (Newtons) / Area (mm^2)
Factor of safety = Ultimate Shear Strength / Shear Stress
I cannot get anything down at all. And I also cannot understand why they have given me Speed and Power. Is there maybe some way to work out the force for the shear stress equation?
Also for your information, this is question 27.11 from Val Ivanoff’s Engineering Mechanics.
Any help would be much appreciated!
This question is giving me a real headache (literally). It should be simple, but I’ve spend probably the last 4-5 hours trying to figure it out. The left side of my brain is redundant.
Homework Statement
The following specifications are used for the design of a flanged coupling between two coaxial shafts:
Speed: 650rpm
Power transmitted: 550 kW
Bolt diameter: 12mm
Pitch-circle diameter: 200mm
Material: Mild steel
Factor of safety: 4
Determine the number of bolts required, assuming the bolts are equally loaded.
Homework Equations
Ultimate Shear Strength of mild steel = 360 N/mm^2
Shear stress (MPa) = Force (Newtons) / Area (mm^2)
Factor of safety = Ultimate Shear Strength / Shear Stress
The Attempt at a Solution
I cannot get anything down at all. And I also cannot understand why they have given me Speed and Power. Is there maybe some way to work out the force for the shear stress equation?
Also for your information, this is question 27.11 from Val Ivanoff’s Engineering Mechanics.
Any help would be much appreciated!